Investigating the reaction Between Sodium Thiosulphate (Na2S2 O3) and Hydrochloric acid (HCl)

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Investigating the reaction Between Sodium Thiosulphate (Na2S2 O3) and Hydrochloric acid (HCl)

Aim

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I am investigating the rate of reaction between Hydrochloric acid

(HCl) and Sodium Thiosulphate (Na2S2O3), when Na2S2O3 is mixed with

water (H20).

Background Knowledge

The rate of a reaction can be speeded up by increasing the

temperature; at a higher temperature the particles move faster and

collide more often, as a result of this the reaction speeds up.

Increasing the concentration of reactants in water will also speed up

the reaction, as there are more reactive particles in the same volume

and therefore more chance of a reaction taking place, which speeds up

the reaction. This is shown in the diagrams below.

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Sulphuric acid (H2SO4)

Water (H2O)

Sodium Carbonate (Na2CO3)

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High Conc. Of Na2CO3

Text Box: Low Conc. Of Na2CO3

These diagrams are from a previous experiment with Sulphuric acid and

Sodium Carbonate.

Breaking up solids into smaller pieces increases the rate of reaction,

as this increases the surface area of the reactant, therefore there is

a larger area for reaction to take place.

However this is not relevant for my investigation as I am only using

liquids, not solids. Also using a catalyst will increase the rate of

reaction, but this is also not relevant for my investigation, as I am

not using any catalysts.

Prediction

I predict that as the concentration of Sodium Thiosulphate (Na2S2O3)

is increased, the rate of reaction will also increase.

I think this is because as the Na2S2O3 concentration is increased it

will react more quickly with the Hydrochloric acid (HCl) as it is more

concentrated so there are more Na2S2O3 particles and therefore more

chance of a Na2S2O3 particle to collide with a HCl particle creating a

reaction and this results in the solution becoming cloudy quicker as

the sulphur is precipitated, as the time taken for the sulphur to go

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