The test is to see if spinach leaves discs can be effected by photosynthesis. I predicted that more disc would float in the light than in the dark. After writing down my hypothesis, I put the discs in water on a petri dish and waited 15 minutes. I then recorded if the in the light were floating or not. I also found out that the disc will also change color when they are in the light or in the dark. The hypothesis is supported when the light does have more disc floating in the petri dish than the dark did. I also determined other things as well such as the the dependent and independent variables, and the control treatments. The independent variable is the amount of oxygen in the discs. The dependent variable is the light, darkness, and the amount
The purpose of this experiment is to determine the absolute configuration of an unknown chiral secondary alcohol using the competing enantioselective conversion (CEC) method. This method uses both R- and S- enantiomers of a chiral acyl-transfer catalyst called homobenzotetramisole (HBTM), in separate parallel reactions, and thin layer chromatography to identify the stereochemistry of the secondary alcohol, whether it be an R- or S- enantiomer. Quantitative analysis was performed using a program called ImageJ after the appropriate picture was taken of the stained TLC plate. The molecular structure of the unknown alcohol was identified using 1H NMR spectroscopy by matching the hydrogens to the corresponding peak.
The data we gathered was tested to be as accurate as possible. Our prediction on the solvents did not support our data that we collected. The cause of this could be due to human error when washing the beets or the cutting of the beets. The beets were not perfectly cut the same size, so some beet pieces were bigger than others which can affect the final the final result. We followed each step and followed the time limits cautiously. I can say if we were to redo the experiment our results would be similar because we would attempt to do the experiment as close as we did the first
This meant that this cuvette (tested under light) should display a higher decrease in DCIP due to the reduction in absorbance (dependent variable) opposed to the other cell fractions tested depending on a sixteen minute period (independent variable). The overall goal was to provide proof, through data, that the cell fractions put under the light during the sixteen minute period would indicate a higher set of chloroplast activity versus the ones put in the
Dependent variable: We are measuring the time taken for the pink indicator to turn clear when hydrochloric acid is added to it. Independent variable: We are changing the molar of hydrochloric acid we are adding to the gelatine cubes. The molars range from 1-3.
... has more CO2 than the negative controls. There will be more spinach circles in the red food coloring than the green and blue food coloring. My hypothesis was supported for both experiments.
What are the effects of different solutions on the size of a cell? To find a solution this problem my group conducted an experiment/lab. The variables changed (Independent Variable) were the solutions, and the results were the change in size of the gummy bear/cell (Dependant Variable). The control group,to compare our results, was a gummy bear that was not put into any solution. The standardized variables were the color of the gummy bear, the same brand of cup, the amount of solution in each cup, and the amount of time each gummy bear spent in the solution.
Going into details of the article, I realized that the necessary information needed to evaluate the experimental procedures were not included. However, when conducting an experiment, the independent and dependent variable are to be studied before giving a final conclusion.
Evaluation: If this experiment was to be redone then more diverse oceanic life would have to be used playing different roles in the water. The experiment performed showed a small projection of the ocean’s course if pH levels rise but by adding more confounding variables then maybe the outcome may have been different. If another researcher is to replicate this experiment it is optimal if they did several different trials to see if the same result occurs like the one just performed.
The overall average of the control Daphnia’s heart rate is 249.38 bpm. 0.01% caffeine’s average is 327.93 bpm, and the caffeine at 0.005% has an average of 268.90 bpm, both making the heart rate speed up. Ethanol had the opposite affect, 0.01% ethanol’s average heart rate for this experiment is 159.58 bpm and 0.005% ethanol had an average of 183.4 bpm. Caffeine has a positive percent change while ethanol has a negative percent change in the data chart. The percent change for 0.01% caffeine is 31.50%change, for 0.005% of caffeine it is 7.83% change and for ethanol 0.01% it is 36.01% change while 0.005% ethanol has a 26.47% change. The standard deviation for the treatments all relatively close. Caffeine 0.01% had a standard deviation of 49.77, 0.005% caffeine’s standard deviation is 58.95. The standard deviation for 0.01% ethanol is 54.19, ethanol 0.005 had a standard deviation of 49.47, and the control groups is 33.31. The p-tests show if and how significant the data
The information gained may support or yield opposite results based on predictions being tested. My independent variable would be time and the dependent one would be the enzyme pectinase. I believe the key feature of my experimentation is the control of most factors so that the influence of a single factor can be seen clearly.
The hypothesis states the plants will grow faster under the sunlight and their growth rate would increase. The data shows that each plants growth and how the temperature effects them from growing. Photosynthesis, transpiration and respiration play a basic part of the plant growth. Yet, there are issues behind plant growth is lack of water, weak soil, and over watering plant. Over watering affects the plants from growing when the soil absorbs the water too fast, and the nutrients won’t have the time to absorb it rapidly. Lack of light could also affect the plant’s growth becomes slow and plants fails to bloom. The solution would be to reduce room temperature by amount 3 Celsius and pour water less frequently. These growing problems are the reason why both group included samples B and C (1st group) and samples A and B (2nd group) were not
My hypothesis states if the pinto beans are watered with the “acid rain” mixture, then the acid rain would negatively affect whether the pinto bean will germinate because acid rain can wash away nutrients and poison plants with toxic metals which could affect whether the bean germinates. According to my data, my hypothesis was correct even though one of the beans with acid rain did germinate but that is 1 out of 20 beans so it’s very unlikely that it would happen again. My hypothesis was correct because my data proves that the pH of the acid rain mixture does affect whether the bean would germinate. Which makes sense because my background information talks about the negative affect of acid rain on plants. In conclusion my hypothesis was correct
In our Biology Lab we did a laboratory experiment on fermentation, alcohol fermentation to be exact. Alcohol fermentation is a type of fermentation that produces the alcohol ethanol and CO2. In the experiment we estimated the rate of alcohol fermentation by measuring the rate of CO2 production. Both glycolysis and fermentation consist of a series of chemical reactions, each of which is catalyzed by a specific enzyme. Two of the tables substituted some of the solution glucose for two different types of solutions. They are as followed, Table #5 substituted glucose for sucrose and Table #6 substituted the glucose for pH4. The equation for alcohol fermentation consists of 6 Carbons 12 Hydrogens 6 Oxygen to produce 2 pyruvates plus 2 ATP then finally the final reaction will be 2 CO2 plus Ethanol. In the class our controlled numbers were at Table #1; their table had 15 mL Glucose, 10 mL RO water, and 10 mL of yeast which then they placed in an incubator at 37 degrees Celsius. We each then measured our own table’s fermentation flasks every 15 mins for an hour to compare to Table #1’s controlled numbers. At
The design for this study will be a simple between subject experiment consisting of one experimental group and one control group. The independent variable will be warm colors. The dependent variable will be mood. The main goal is to determine if the independent variable will influence or cause difference in the specified dependent variable. The experiment group will spend 60 minutes in a warm paint color room and their mood will be measured. The control group will spend 60 minutes in a neutral paint color room and their mood will be measured.
Dependent Variables Amount of vitamin C in fruit juices. Controlled Variable Same amount of liquid for each fruit juice.... ... middle of paper ... ...