Determine the Concentration of Calcium Hydroxide
2HCl (aq) + Ca (OH)2(aq) [IMAGE] 2H20(l) + CaCl2(s)
In this experiment I need to find out the concentration of calcium
hydroxide. I am provided with 250cm3 of limewater, which has been made
such that it contains 1g dm-3 of calcium hydroxide. To increase the
accuracy of the results it would be helpful if the volume of the
alkali equalled the volume of the acid used, and I know that the
concentration of the alkali is approximately 1gmdm-3 which is roughly
equal to 0.013mol by using the equation
Mole = Mass / Mass of one mole
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=0.013 moldm-3
Also I am provided with hydrochloric acid, which has a concentration
of exactly 2.00 moldm-3. The acid is too concentrated to be used, so I
need to dilute it. Using acid that is twice the molar of the alkali
should result in equal volumes of each being used. So
* 0.013 * 2 = 0.026 M
*and taking the molar of the acid down by a factor of one hundred
would work well.
Calcium hydroxide and hydrochloric acid are in the ratio 1:2.
For this, I will need the pipette and the pump to collect exactly 25cm3
taking into account parallax errors where the level of the 25cm3 line
is at the bottom of the meniscus. By placing this in a volumetric
flask and topping it up to 500cm3 with distilled water taking into
account the parallax error again. Stopper the flask and shake the
flask thoroughly (by inverting it a number of times) so that the
entire volume is of precisely the same concentration. This will have
taken the molar down to 0.2M so by repeating this process again the
molar will be taken down to 0.02M, which is now ready for the
titration. I performed the titration with the hydrochloric acid of
0.02 moldm-3 in a burette and 25cm3 calcium hydroxide in a conical
flask. I considered the first reading as a rough reading and took
another three readings, so that no anomalous result might occur.
We then took 1ml of the 1% solution from test tube 1 using the glucose pipette and added it to test tube 2, we then used the H2O pipette and added 9ml of H2O into test tube 2 creating 10ml of 0.1% solution
taken into account. It is also best to make sure you are working in a
Apparatus: * 1 measuring cylinder * 1 test tube * 1 stop clock * A large gelatine cube containing indicator and NaOH * Hydrochloric acid ranging from 1-3 molars * A scalpel Diagram: Method: * Take the large gelatine cube and cut into 15 equal pieces * Place on piece of the cube into the test tube * Measure out 10mls of HCl in the measuring cylinder * Pour the HCl into the test tube with the gelatine cube and start the clock * Time how long it takes for the pink colour inside the gelatine cube to completely disappear * You will also notice that the cube dissolves slightly * Record your results and repeat this same process 3 times for each molar of acid: § 1 molar § 1.5 molar § 2 molar
Volume's Effect on a Copper Sulphate Solution We are trying to find out if the current though a copper sulphate solutions volume is increased. To find this information out I shall perform an experiment using the following equipment; · 1 power pack · 1 beaker · 2 carbon rods for anode and cathode · 1 ammeter · 1 measuring cylinder · 2 crocodile clip wirers I shall also be using 60cm3 volume of copper sulphate in my preliminary results to decide upon the concentration of copper sulphate and the voltage I shall use. The following diagrams show the step by step process in which I will do my experiment; [IMAGE] [IMAGE] [IMAGE] [IMAGE] I will take 10 readings from 10cm3 to 100cm3. I will repeat my experiment to give my experiment a fair average. I will keep the power pack the beaker the carbon rods the crocodile clips the ammeter the concentration of copper sulphate and the measuring cylinder the same each time I do the experiment this experiment.
Experiment is to investigate the rate of reaction between hydrochloric acid and calcium carbonate Hydrochloric acid + Calcium Carbonate Þ Calcium Chloride + Water + Carbon Dioxide 2HCl (aq) CaCo3 (s) CaCl2(s) H2O (aq) CO2 (g) There are a number of variables in this experiment and these are listed below as input variables and outcome variables.
Reaction 2: H = 50 x 4.18 x -10.3" H = -2152.7 This value is for 1.37g of calcium oxide, not 56.1g, which is its relative molecular mass. Therefore: H =
Determining the Concentration Of Limewater Solution Aim: The aim of this experiment is it to find out the concentration of Limewater by performing a titration with hydrochloric acid which has concentration exactly 2.00M.. What is required for me is that I have to design my own experiment and chose the right and appropriate apparatus and equipment. I will be provided with 250cm3 of limewater, which has been made to which contains approximately 1g/dm3 of calcium Hydroxide. This hypothesis from www.studentcentral.co.uk We were also give Hydrochloric acid (HCl) with a concentration of 2.00 mol/dm3 normal laboratory apparatus was also given and so was an indicator.
Burette Stand + Clamps Measuring Cylinder Safety Goggles Beaker Thermometer Stopwatch Kettle + water Small Funnel Delivery Tube + Bung I have chosen to use a measuring cylinder to make my experiment as accurate as I possibly can. I will be wearing the provided safety goggles at all times to protect my eyes, as hydrochloric acid is an. irritant that may prove dangerous if it makes contact with the eye. Theory The following theories will help me decide which variable I will change in my experiment to investigate the rate of reaction using calcium carbonate and hydrochloric acid. Temperature - Collision Theory = =
The Enzyme Concentration and The Volume of Juice As the enzyme concentration increases so too does the volume of juice. This is because as the concentration of enzyme molecules increase there is more chance of a collision with an apple substrate molecule. If the chance of a collision is increased then the number of collisions will increase resulting in a higher rate of reaction. The enzyme combines with the substrate to form an enzyme-substrate complex.
I will not add a catalyst to my solution and I will not stir my solution. · I will use 25cm3 of hydrochloric acid. · I will use 1g of calcium carbonate.
Investigate how the concentration of hydrochloric acid effects the rate at which it reacts with calcium carbonate
of Copper Sulphate. To do this I plan to work out the amount of water
second test tube also add 6 mL of 0.1M HCl. Make a solution of 0.165
6. I then rinsed out the beaker and glass rod into the flask to make
The purpose of this experiment is to use our knowledge from previous experiments to determine the exact concentration of a 0.1M sodium hydroxide solution by titration (Lab Guide pg.141).