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Synthesis lab report
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Discussion
The fifth experiment of the semester entails a synthesis reaction geared towards analyzing the structure of a product. The starting material is isopentyl alcohol. When reacted with acetic acid with sulfuric acid as a solvent, isopentyl alcohol produces isopentyl acetate, which is the goal product, as shown in the reaction below:
Once isopentyl acetate is produced, it will become important to analyze its structure and purity.
This experiment involves performing various techniques, including heating under reflux, separation, drying, distillation, gas chromatography (GC), infrared spectroscopy (IR spectroscopy), and nuclear magnetic resonance (1H NMR). Heating under reflux is important to overcome any activation barrier of energy that may be present in order to complete the reaction.
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Separation allows an organic layer to be separated from a solid following reflux, and it also permits an organic layer to separated from an aqueous layer following washings to ensure purification. Drying and distillation also help ensure purification by removing excess water and solid from the organic layer. GC, IR spectroscopy, and 1H NMR are three of many various ways available to analyze the components and structure of a compound. GC allows separation of compounds based on boiling point and attraction to materials inside of the GC. IR allows separation of compounds based on UV light. 1H NMR allows separation of compounds based on magnetic properties pertaining to hydrogen atom surroundings. The experiment began with 13.22 grams of isopentyl alcohol, which was subsequently mixed with 17 mL of acetic acid and 1.0 mL of sulfuric acid. This mixture was refluxed under heat for approximately 50 minutes to ensure that the reaction could occur following the breaking of an activation barrier. Once reflux ended, the mixture was allowed to cool to room temperature and then poured into a separatory funnel. In the separatory funnel, the solution was washed with 50 mL of water and 60 mL (two 30 mL washes) of sodium bicarbonate. Unfortunately, following all of the washings, most of my organic solution ran out of the separatory funnel. I was left with only a few drops of my solution. Following the washings, the organic layer was dried with sodium or magnesium sulfate and separated from the solid via gravity filtration. Due to the low amount of organic solution remaining, I could not perform distillation or weigh the dried solid. I estimated that my remaining solution weighed approximately less than 1 gram, and I performed my calculations based on that estimation. Then, I proceeded to perform GC and IR spectroscopy on my remaining sample. The results of the gas chromatography were consistent with the reaction performed. I had a small acetone peak, a large isopentyl acetate peak, and a smaller isopentyl alcohol peak; however, the acetone peak is negligible because it was simply used to wash the needle prior to GC. From my area calculations, I determined that the percent composition of isopentyl acetate for my solution was approximately 76%, whereas the percent composition of isopentyl alcohol was 24%. This chart also allowed me to determine the actual mass of my banana oil (less than 0.76 grams compared to less than 1 gram) and the actual percent yield of my banana oil (less than 76% yield). This shows that my banana oil was somewhat pure, but it was not completely pure. I think the GC would have gone better if I had more banana oil left. In addition, the IR spectroscopy results showed that my banana oil contained a variety of different bonds. For example, it had an ester group, a C-O bond, and a carboxylic acid group; however, the IR also revealed impurities, such as an –OH group (hydroxide/alcohol). This –OH group is probably from the isopentyl alcohol. Here are the complete results of my IR spectroscopy run: IR (cm-1): 3553.57, 3464.68, 2960.20, 2722.90, 2748.49, 2072.67, 1742.83, 1466.24, 1367.31, 1243.61, 1171.13, 1135.51, 1056.44, 961.67, 922.33, 900.69, 854.99, 818.43, 769.88, 635.40, 606.36 Please note that the IR was run with sodium chloride salt plates. Although I did not perform a 1H NMR run myself, the results were provided for students. The 1H NMR separates compounds based on their magnetic attraction to surrounding hydrogens. The 1H NMR results are as follows: 1H NMR: (CDCl3, 200 MHz) δ 0.886 (2 H), 0.919 (2 H), 1.479 (0 H), 1.514 (1 H), 2.020 (0 H), 4.038 (3 H), 4.073 (3 H), 4.108 (3 H) These results allowed me to confirm that the structure of isopentyl acetate is as follows: Although I am sure of my GC results, I am unsure of my IR and the 1H NMR results. I believe I need more practice with reading the results and determining the structure of compounds. Even though I took caution with my experiment, it was still prone to many errors. The most notable error was the spillage of my banana oil following use of the separatory funnel. Although it may not have affected the components of my organic layer, I could not perform distillation to decrease impurities in my solution. Distillation may have led to different results for the IR spectroscopy, and possibly even the GC. Also, I would have been able to weigh the solid isopentyl acetate following distillation, but this was not possible. If I had the chance, I would redo this experiment again and take extra caution with the separatory funnel. Other errors in my experiment could have been letting the solution reflux under heat for too little or too much time. If I did not reflux long enough, the reaction may not have been driven to completion. If I refluxed too long, the reaction product may have burned off. Additionally, I could have dried my product with too much or too little sodium or magnesium sulfate. If I did not dry the solution enough, excess water could have remained, which could have made my IR spectroscopy reading strange. If I dried to solution too much, the sodium or magnesium sulfate could have soaked up some of the solution, thereby decreasing the amount available for distillation, GC, and IR spectroscopy. I would need to repeat this experiment multiple times before providing any real data to ensure consistent results. This experiment proved to involve challenging tasks, but I am beginning to grasp the concepts of GC, IR spectroscopy, and 1H NMR. Conducting a synthesis and proving its purity is difficult, and I would want to repeat this experiment again in order to obtain a more accurate result. I hope to become more comfortable with performing synthesis reactions, as well as utilizing gas chromatography, infrared spectroscopy, and nuclear magnetic resonance techniques, in future experiments. Questions – IUPUI Custom Edition 2) Carbon dioxide escaped during the sodium bicarbonate washing.
CH3COOH + NaHCO3 ⇒ CH3COONa + CO2 + H2O
H2SO4 + 2NaHCO3 ⇒ Na2SO4 + CO2 + 2H2O
4) (a) If you failed to dry the reaction flask after washing it with water, then your newly added solution would contain water. While this could be removed through drying and distillation, there could still be some excess water. This would make your isopentyl acetate dilute. Furthermore, water would hinder the IR spectroscopy process by harming the salt plates used in the machine.
(b) If you forgot to add the sulfuric acid, then your reaction would not work. You would not produce isopentyl acetate because the sulfuric acid is required to drive the reaction forward towards isopentyl acetate.
(c) If you used twice the amount of acetic acid specified in the procedure, then there would be excess acetic acid in the solution. This may lead to a smaller yield of isopentyl acetate. It would also be very important to perform the washes with the separatory funnel diligently to get rid of the excess acetic acid, as well as distillation. You may observe an extra peak on your gas chromatograph or your IR
spectroscopy. (d) If you left of the sodium bicarbonate washing step, then your organic layer would have a higher chance of containing impurities. You only want the isopentyl acetate, but your organic layer would most likely still contain any unreacted starting materials in excess. The sodium bicarbonate washes out any excess of these starting materials or other impurities. Thus, your organic solution would possibly be impure. (e) If your thermometer bulb was 1 cm higher than it should have been, then you may have obtained an inaccurate temperature reading. Also, some of the solution could have escaped into the air as a gas.
Then the reaction tube was capped but not tightly. The tube then was placed in a sand bath reflux to heat it until a brown color was formed. Then the tube was taken out of the sand bath and allowed to cool to room temperature. Then the tube was shaken until a formation of a white solid at the bottom of the tube. After formation of the white solid, diphenyl ether (2 mL) was added to the solution and heated until the white solid was completely dissolved in the solution. After heating, the tube was cooled to room temperature. Then toluene (2 mL) was added to the solution. The tube was then placed in an ice bath. Then the solution was filtered via vacuum filtration, and there was a formation of a white solid. Then the product was dried and weighed. The Final product was hexaphenylbenzene (0.094 g, 0.176 mmol,
The actual amount of crude product was determined to be 3.11 grams. The percent yield of the crude product was determined to be 67.75 %. The actual amount of pure product formed was found to be 4.38 grams. The percent yield of the pure product was determined to be 95.42%. Regarding the thin layer chromatography, the line from the solvent front is 8 centimeters.
Extraction is a separation method that is often used in the laboratory to separate one or more components from a mixture. Sucrose was separated at the beginning because it is the most immiscible and it’s strongly insoluble. Next Acetylsalicylic Acid was separated which left Acetanilide alone. Variety steps could have led to errors occurring. For example the step of separation, when dichloromethane layer was supposed to be drained out, it could be possible some aqueous layer was drained with it. Which could make the end result not as accurate. Also errors could have occurred if possibly some dichloromethane was not drained out. Both way could interfere with end result of figuring the amount of each component in the mixture. The solids percentage were 22.1% more than the original. That suggests that solids weren’t separated completely which clarifies the reason the melting points that were recorded were a slightly lower than the actual component’s melting point. The melting point for Acetylsalicylic Acid is 136 C but that range that was recorded during the experiment was around 105 C to 118 C. The melting points were slightly lower than the literature value. Sucrose was the purest among all component due to its higher melting point which follows the chemical rule that the higher the melting point the more pure the component
Perhaps, a different drying agent may also be used like MgSO4. Another improvement may be to use a curved Pasteur pipette to remove the appropriate liquid. Using a test tube to add anhydrous sodium sulfate resulted in the drying agent being on the sides of the tube. Hence, to improve this error, a glass with a flat bottom may be used.
2-ethyl-1,3-hexanediol. The molecular weight of this compound is 146.2g/mol. It is converted into 2-ethyl-1-hydroxyhexan-3-one. This compounds molecular weight is 144.2g/mol. This gives a theoretical yield of .63 grams. My actual yield was .42 grams. Therefore, my percent yield was 67%. This was one of my highest yields yet. I felt that this was a good yield because part of this experiment is an equilibrium reaction. Hypochlorite must be used in excess to push the reaction to the right. Also, there were better ways to do this experiment where higher yields could have been produced. For example PCC could have been used. However, because of its toxic properties, its use is restricted. The purpose of this experiment was to determine which of the 3 compounds was formed from the starting material. The third compound was the oxidation of both alcohols. This could not have been my product because of the results of my IR. I had a broad large absorption is the range of 3200 to 3500 wavenumbers. This indicates the presence of an alcohol. If my compound had been fully oxidized then there would be no such alcohol present. Also, because of my IR, I know that my compound was one of the other 2 compounds because of the strong sharp absorption at 1705 wavenumbers. This indicates the presence of a carbonyl. Also, my 2,4-DNP test was positive. Therefore I had to prove which of the two compounds my final product was. The first was the oxidation of the primary alcohol, forming an aldehyde and a secondary alcohol. This could not have been my product because the Tollen’s test. My test was negative indicating no such aldehyde. Also, the textbook states that aldehydes show 2 characteristic absorption’s in the range of 2720-2820 wavenumbers. No such absorption’s were present in my sample. Therefore my final product was the oxidation of the secondary alcohol. My final product had a primary alcohol and a secondary ketone
For this experiment we have to use physical methods to separate the reaction mixture from the liquid. The physical methods that were used are filtration and evaporation. Filtration is the separation of a solid from a liquid by passing the liquid through a porous material, such as filter paper. Evaporation is when you place the residue and the damp filter paper into a drying oven to draw moisture from it by heating it and leaving only the dry solid portion behind (Lab Guide pg. 33.).
Every 5 minutes, a small amount of mixture was dissolved in acetone (0.5 mL) and was spotted onto a thin layer chromatography (TLC) plate, which contained an eluent mixture of ethyl acetate (2 mL) and hexanes (8 mL). The bezaldehyde disappearance was monitored under an ultraviolet (UV) light. Water (10 mL) was added after the reaction was complete, and vacuum filtrated with a Buchner funnel. Cold ethanol (5 mL) was added drop-by-drop to the dried solid and stirred at room temperature for about 10 minutes. Then, the solution was removed from the stirrer and place in an ice bath until recrystallization. The recrystallized product was dried under vacuum filtration and the 0.057 g (0.22 mmol, 43%) product was analyzed via FTIR and 1H NMR
The product was recrystallized to purify it and the unknown filtrate and nucleophile was determined by taking the melting points and performing TLC. Nucleophilic substitution reactions have a nucleophile (electron pair donor) and an sp3 electrophile (electron pair acceptor) with an attached leaving group. This experiment was a Williamson ether synthesis usually SN2, with an alkoxide and an alkyl halide. Conditions are favored with a strong nucleophile, good leaving group, and a polar aprotic solvent.
The C-H (sp3) hydrogens from our product displayed at wavelength 2959 cm-1 correlates to the methyl groups located on the ends of isopentyl acetate4. A really prominent, strong peak located at 1742 cm-1 shows that a C=O ester stretch is located in the product, along with at 1244 cm-1 the spectrum shows a strong peak representing the C(=O)-O stretch that is crucial to the structure of isopentyl acetate. Shown in my IR spectrum is a weak O-H (H-bonded) peak at 3464 cm-1 which shows that I have an impurity of isopentyl alcohol in my product. Isopentyl alcohol has similar boiling points and density as my product so the impurity could have easily boiled out with the isopentyl acetate during distillation. The isopentyl alcohol was also present in my 1H-NMR spectrum backing up the impurity peak at 3464
The objective of this experiment was to perform extraction. This is a separation and purification technique, based on different solubility of compounds in immiscible solvent mixtures. Extraction is conducted by shaking the solution with the solvent, until two layers are formed. One layer can then be separated from the other. If the separation does not happen in one try, multiple attempts may be needed.
water than last time, less products were formed, and most of the ester was used
I blended on high to make the potatoes more liquid-like. I grabbed the cheesecloth and placed on the top of the blender. I poured the potato extract on the container and labeled it. I found out that I have to make 1% sugar solution so I grabbed the sugar and measured into 5 grams on the scale. I added 5 grams of sugar on 250 ml graduated cylinder and poured the water into the cylinder. I mixed the sugar with water and poured it into the saucepan. I refilled the water into the graduated cylinder and poured into the saucepan. I turned on the heat of the stove and saw the sugar dissolved. I poured into a container and labeled 1% sugar solution. I repeated the same thing with 1% salt solution by using 1 gram of salt and filled the water into graduated cylinder by 100 ml. I answered question three. In the first experiment, I grabbed four transfer pipets and used it to put solutions into the test tubes by 3ml. I labeled it and placed into the plastic cups so it can stand upright. I grabbed each test tube and poured 2 ml of catalase solution into it. I also tapped and swirled to measure the bubbles by using the ruler. I wrote the numbers into the lab report. In the second experiment, I labeled the room
Analysis of Aspirin Tablets Aim --- To discover the percentage of acetylsalicylic acid in a sample of aspirin tablets. ----------------------------------------------------------------- In order to do this, the amount of moles that react with the sodium hydroxide must be known. This is achieved by using the method of back titration.
Firstly, an amount of 40.90 g of NaCl was weighed using electronic balance (Adventurer™, Ohaus) and later was placed in a 500 ml beaker. Then, 6.05 g of Tris base, followed by 10.00 g of CTAB and 3.70 g of EDTA were added into the beaker. After that, 400 ml of sterilized distilled water, sdH2O was poured into the beaker to dissolve the substances. Then, the solution was stirred using the magnetic stirrer until the solution become crystal clear for about 3 hours on a hotplate stirrer (Lab Tech® LMS-1003). After the solution become clear, it was cool down to room temperature. Later, the solution was poured into 500 ml sterilized bottle. The bottle then was fully wrapped with aluminium foil to avoid from light. Next, 1 mL of 2-mercaptoethanol-β-mercapto was added into fully covered bottle. Lastly, the volume of the solution in the bottle was added with sdH2O until it reaches 500 ml. The bottle was labelled accordingly and was stored on chemical working bench.
The first experiments investigate the order of reaction with respect to the reactants; hydrogen peroxide, potassium iodide and sulphuric acid by varying the concentrations and plotting them against 1/time. An initial rate technique is used in this experiment so ‘the rate of reaction is inversely proportional to time.’ To find the order of reaction in respect to the reactants, 1/time is plotted against the concentration of Hydrogen Peroxide using the equation: