Part B
Since 1-octanol was the least polar among 3 alcohols used in this part, so it was found to be insoluble in water but soluble in hexane. This was due to the longer chain of carbons makes compounds more hydrocarbon-like.
1-Butanol with intermediate polarity was soluble in both highly polar water and non polar hexane as 1-butanol can be either polar or non polar compound. 1-Butanol was polar based on the general rule of thumb stated that each polar group will allow up to 4 carbons to be soluble in water. Also, 1-butanol can be non polar due to their carbon chains, which are attracted to the non polarity of the hexane.
Methanol was the most polar among 3 alcohols used in this part, hence was soluble in water as both water and methanol were polar. However, methanol was partially soluble in hexane because the Van der Waals interaction between methanol
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molecules was therefore too strong to enable mixing with non polar hexane. Part C The pairs of water + ethyl alcohol (test tube A) and hexane + methylene chloride (test tube D), were found to be miscible, while water + diethyl ether (test tube B) and water + hexane (test tube C) were found to be immiscible. For solution in test tube A, both compounds were polar and like dissolves like while in test tube C, both compounds have different polarity. In spite of the fact that diethyl ether in test tube B is essentially polar compound, but it was considered less polar than water. So diethyl ether was not polar enough to dissolve together with highly polar water. This situation same goes to methylene chloride in test tube D. Methylene chloride is only slightly polar and is often regarded as being non polar due to the presence of halogen atoms. Part D Benzoic acid was insoluble in water and shares some of the same solubility properties as ethyl 4-aminobenzoate.
Benzoic acid does not dissolved in water unless the water is hot because the non polar hydrocarbon part outweighs the effect of polar –COOH part as non polar part was hydrophobic. So there was no hydrogen bonding took place and it was insoluble as the final result. Meanwhile, for ethyl 4-aminobenzoate not mixing with water due to greater chain of carbons in amino group makes it less polar than benzoic acid.
When benzoic acid paired with 1.0 M NaOH, it was observed that both compounds were soluble. Upon the addition of 6.0 M HCl into this solution, benzoic acid became insoluble. Benzoic acid was also insoluble in 1.0 M HCl. Ethyl 4-aminobenzoate was found to be insoluble in 1.0 M NaOH and soluble in 1.0 M HCl. But then, after adding 6.0 M NaOH into the test tube C (mixture of ethyl 4-aminobenzoate and 1.0 M HCl), a white powdery solid (undissolved compound) was formed. These demonstrate that both the acid and base became more soluble when they were ionized and less soluble when they were
not.
The theoretical yield of the m-nitrobenzoate was de-termined to be 4.59 grams. The actual amount of crude product was determined to be 3.11 grams. The percent yield of the crude product was determined to be 67.75 %. The actual amount of pure product formed was found to be 4.38 grams. The percent yield of the pure product was determined to be 95.42%. Regarding the thin layer chromatography, the line from the solvent front was 8 centimeters.
The goal of this two week lab was to examine the stereochemistry of the oxidation-reduction interconversion of 4-tert-butylcyclohexanol and 4-tert-butylcyclohexanone. The purpose of first week was to explore the oxidation of an alcohol to a ketone and see how the reduction of the ketone will affect the stereoselectivity. The purpose of first week is to oxidize the alcohol, 4-tert-butylcyclohexanol, to ketone just so that it can be reduced back into the alcohol to see how OH will react. The purpose of second week was to reduce 4-tert-butylcyclohexanol from first week and determine the effect of the product's diastereoselectivity by performing reduction procedures using sodium borohydride The chemicals for this lab are sodium hypochlorite, 4-tert-butylcyclohexanone
The primary goal of this laboratory project was to identify an unknown compound and determine its chemical and physical properties. First the appearance, odor, solubility, and conductivity of the compound were observed and measured so that they could be compared to those of known compounds. Then the cation present in the compound was identified using the flame test. The identity of the anion present in the compound was deduced through a series of chemical tests (Cooper, 2009).
Solubility test was used to determine if unknown white compound was soluble in water. To conduct the solubility test, many materials were used such as flask, glass rod, scale, and chemical used was unknown white compound. First, 0.25 gram of unknown white compound carefully measured on scale. Then, the 0.25 gram of unknown white compound added to 100 mL of water and dissolved it using the glass rod. While the unknown
The boiling point of the product was conducted with the silicone oil. Lastly, for each chemical test, three test tubes were prepared with 2-methylcyclohexanol, the product, and 1-decene in each test tube, and a drop of the reagent were added to test tubes. The percent yield was calculated to be 74.8% with 12.6g of the product obtained. This result showed that most of 2-methylcyclohexanol was successfully dehydrated and produced the product. The loss of the product could be due to the incomplete reaction or distillation and through washing and extraction of the product. The boiling point range resulted as 112oC to 118oC. This boiling point range revealed that it is acceptable because the literature boiling point range included possible products, which are 1-methylcyclohexene, 3-methylcyclohexene, and methylenecyclohexane, are 110 to 111oC, 104oC, and 102 to 103 oC. For the results of IR spectroscopy, 2-methylcyclocahnol showed peaks at 3300 cm-1 and 2930 cm-1, which indicated the presence of alcohol and alkane functional group. Then, the peak from the product showed the same peak at 2930 cm-1 but the absence of the other peak, which indicated the absence of the alcohol
In order to separate the mixture of fluorene, o-toluic acid, and 1, 4-dibromobenzene, the previously learned techniques of extraction and crystallization are needed to perform the experiment. First, 10.0 mL of diethyl ether would be added to the mixture in a centrifuge tube (1) and shaken until the mixture completely dissolved (2). Diethyl ether is the best solvent for dissolving the mixture, because though it is a polar molecule, its ethyl groups make it a nonpolar solvent. The compounds, fluorene and 1, 4-dibromobenzene, are also nonpolar; therefore, it would be easier for it to be dissolved in this organic solvent.
In a separate beaker, acetone (0.587 mL, 8 mmol) and benzaldehyde (1.63 mL, 16 mmol) were charged with a stir bar and stirred on a magnetic stirrer. The beaker mixture was slowly added to the Erlenmeyer flask and stirred at room temperature for 30 minutes. Every 10 minutes, a small amount of the reaction mixture was spotted on a TLC plate, with an eluent mixture of ethyl acetate (2 mL) and hexanes (8 mL), to monitor the decrease in benzaldehyde via a UV light. When the reaction was complete, it was chilled in an ice bath until the product precipitated, which was then vacuum filtrated. The filter cake was washed with ice-cold 95% ethanol (2 x 10 mL) and 4% acetic acid in 95% ethanol (10 mL). The solid was fluffed and vacuum filtrated for about 15 minutes. The 0.688 g (2.9 mmol, 36.8%, 111.3-112.8 °C) product was analyzed via FTIR and 1H NMR spectroscopies, and the melting point was obtained via
Benzyl bromide, an unknown nucleophile and sodium hydroxide was synthesized to form a benzyl ether product. This product was purified and analyzed to find the unknown in the compound. A condenser and heat reflux was used to prevent reagents from escaping. Then the solid product was vacuum filtered.
Performing this experiment, we used the technique called Acid-Base extraction to isolate Eugenol, which is one of the main ingredients of clove oil. Acid-Base extraction is the most efficient method for isolating organic component; it is efficient because it purifies the acid and base mixture based on their chemical identities. We have seen throughout this experiment that acid and base play an important role, when it comes to solubility in water. Our basic knowledge of acid and base is acid is a proton donor and base is a proton acceptor. This ideology helps us to understand why organic compounds are not soluble in water. When compounds tend to be insoluble, we have to use acid and base reaction, to change its solubility. The changes that occurred
2-butoxyethanol, a colorless liquid with a mild odor, is used in different paints, primers, and kinds of ink, along with numerous household cleaning products commonly found, to remove substances such as grease and oils. However, the usage of 2-butoxyethanol comes with risks as well. 2-butoxyethanol’s risks outweigh the rewards of it being used.
Hydrolysis of aspartame under acidic or basic conditions results in aspartic acid, phenylalanine and methanol. Several solutions can be prepared in order to study the amino acids of aspartame. With TLC analysis, we were able to observe the polarity of each of the solutions prepared. Out of all the solutions, aspartic acid has the lowest Rf value because it is a charged amino acid, therefore it is polar. The solution with the highest Rf is phenylalanine because it is a hydrophobic amino acid.
Ethanol has five C-H bonds, one C-O bond, one C-C bond and one O-H bond therefore the calculation would be: (5 412) + 360 + 348 + 463 = 3231. Propan-1-ol has seven C-H bonds, 2 C-C bonds, one C-O bond and one O-H bond therefore the calculation would be: (7 412) + 360 + (2 348) + 463 = 4403. Butan-1-ol has nine C-H bonds, 3 C-C bonds, one C-O bond and one O-H bond therefore the calculation would be: (9 412)
Ensure gloves are worn at all times when handling strong acids and bases within the experiment of the preparation of benzocaine. 4-aminobenzoic acid (3.0g, 0.022 moles) was suspended into a dry round-bottomed flask (100cm3) followed by methylated sprits (20 cm3). Taking extra care the concentrated sulphuric acid of (3.0 cm3, 0.031 moles) was added. Immediately after the condenser was fitted on, and the components in the flask were swirled gently to mix components. It should be ensured that the reactants of the concentrated sulphuric acid and the 4-aminobenzoic acid were not clustered in the ground glass joint between the condenser itself and the flask. In order to heat the mixture to a boiling point, a heating mantle was used and then further left for gently refluxing for a constituent time of forty minutes. After the duration of the consistent forty minutes the rou...
Dissolvability is most prominent between materials with comparable polarities and this is characterized by hydrogen
Four drops of the unknown liquid (L21) or 50mg of solid unknown (S21) is mixed with 2mL of water in a test tube. 2mL of 3M sodium Hydroxide was then added. 3mL of iodine solution was added. The results of the reaction were