Wait a second!
More handpicked essays just for you.
More handpicked essays just for you.
Electrolysis experiment
Electrolysis experiment
Electrolysis experiment
Don’t take our word for it - see why 10 million students trust us with their essay needs.
Recommended: Electrolysis experiment
The purpose of the experiment is to perform five electrochemical reactions using a voltage probe. The overall goal is then to measure the voltage, compare it to the theoretical values, calculate the concentration of the cells, and identify unknown metals in the cells. The theoretical E° of the Cu-Pb voltaic cell was calculated simply by subtracting the E°cathode by the E°anode (E_cell^o=E_cathode^o-E_anode^o), using the given standard reduction potentials. In the reaction, Copper, the cathode, was reduced and Lead, the anode, was oxidized. The E°cathode for Copper had a potential of .34 V. The E°anode Lead had a potential of -.13 V. Thus, the calculated theoretical E° of the cell was determined to be .47 V. The average experimental E° for the Cu-Pb cell was found to be .486 V, giving a 3.404% error when compared to the theoretical value. Cu-Pb Voltaic Cell: Reduction Half-Reaction Cu_((aq))^(2+)+2e^-→Cu_((s) ) Oxidation Half-Reaction 〖Pb〗_((s))→〖Pb〗_((aq))^(2+)+2e^- Balanced Chemical Equation Pb_((s))+Cu_((aq))^(2+)→Pb_((aq))^(2+)+Cu_((s)) Standard Cell Notation Pb_((s)) |〖Pb〗_((aq))^(2+) ||Cu_((aq))^(2+) |Cu_((s) ) The …show more content…
E_cell^o was determined to be 0 V since the same metal was used as the electrodes. In doing so, the differences in the standard reduction potentials was 0 V. The R value, the ideal gas constant is given in 8.314 J/(mol K), T is the temperature at standard conditions (298.15 K), n is the number of electrons transferred (2 in this case), and F is the Faraday Constant of 96485.3399 J/(V mol). The reaction quotient, Q, was determined to equal the concentration of the concentrated Copper ion divided by the diluted Copper ion concentration (Q=([Cu_diluted^(2+)])/([Cu_concentrated^(2+)])= .05 M). The average corrected Ecell was found to be .042 V, givng a 10.52% error when compared to the theoretical
What were we trying to accomplish with this experiment? What method did we implement to accomplish the task? What techniques were used to purify and identify the product(s) of the reaction?
“Chemistry is the study of substances; their properties, structure, and the changes they undergo” (Lower). Chemistry is the study of all the stuff in the world and especially how they change. My experiment deals mostly with the change of substances. Some of the concepts involved in my experiment are Oxidation/Reduction (redox) reactions, electrolysis, pH, and electrical currents. A redox reaction is a reaction in which there is a transfer of electrons from one substance to another. There are two paired parts to a redox reaction: the oxidation and the reduction. The oxidation is the loss of electrons while the reduction is the gain of electrons. They always occur together because one substance has to receive the electrons that another substance is giving up. Electrolysis is a process where electricity goes through a liquid, which causes chemical reactions to occur. pH is the measure of how acidic or basic something is. More exactly, it is, at least indirectly, the number of hydrogen ions there are in a liter of solution. A hydrogen ion is a hydroge...
Introduction: The purpose of this lab was to cycle solid copper through a series of chemical forms and return it to its original form. A specific quantity of copper undergoes many types of reactions and goes through its whole cycle, then returns to its solid copper to be weighted. We observed 5 chemical reactions involving copper which are: Redox reaction (which includes all chemical reactions in which atoms have their oxidation state changed), double displacement reaction, precipitation reaction, decomposition reaction, and single displacement reaction. 4HNO3(aq) + Cu(s) --> Cu (NO3)2(aq) + 2H2O (l) + 2NO2(g) Oxidation reduction reaction Cu (NO3)2(aq) + 2 NaOH (aq) --> Cu (OH)2(s) + 2 NaNO3(aq) Precipitation Reaction Cu (OH)2(s) + heat --> CuO (s) + H2O (l) Decomposition reaction CuO (s) + H2SO Data Results: (mass of copper recovered / initial mass of copper) x 100 Mass of copper recovered: 0.21 Initial mass of copper: 0.52 (0.21/0.52)x100 =40.38%.
The compound was predicted to be Copper I Sulfide because the error analysis of the final mass was only 1.17% and the error analysis of Copper II Sulfide was 15.6%. Also the empirical ratio is 2:1 which fits Copper I Sulfide (Cu2S), but not Copper II Sulfide which has an empirical ratio of 1:1. The % composition and mass : mass conversion was calculated for both Copper I Sulfide and Copper II Sulfide in order to make sure the results and conclusions were as accurate as possible.
The purpose of this lab is to determine the empirical formula of copper oxide (CuxOy) through a single-displacement reaction that extracts the copper (Cu) from the original compound. In order to do this, hydrochloric acid (HCl) was mixed in with solid CuxOy; the mixture was stirred until the CuxOy was totally dissolved in the solvent. Zinc (Zn) was then added to the solution as a way to enact a single displacement reaction in which Cu begin to form on the Zn; the Cu gets knocked off the Zn through gentle stirring. To isolate the Cu, the supernatant liquid was decanted and the Cu was then washed with first water then second, isopropyl alcohol. Once done, the hydrated Cu is transferred onto an evaporating dish where it was heated multiple times
In procedure A, one must know what an electrolyte is, which is a substance that produces an electrically conducting solution when dissolved in a polar solvent, in this case water is the solvent. Based on the results of the experiment, it can be concluded that the sodium chloride solution best conducts electricity. This is due to ions being separated into Na+ and Cl- ions from the original NaCl. In other words, NaCl(s) becomes Na+ (aq) + Cl- (aq). In doing so, allows electricity to flow into the solution.
In the first part of this project, two cation elimination tests and one cation confirmation test were performed. 10 drops of 4 cation solutions: potassium, zinc(II), copper(II)
Blister copper then goes through the fire refining and then cast into copper anodes and placed in an electrolytic cell. Each copper anode is placed in a tank made of concrete. A sheet of copper is placed on the opposite end of the concrete tank to become the cathode or the negative terminal. An acidic copper sulfate solution is then poured into the concrete tanks; this forms the e...
Electrolysis is the only permanent hair removal methods that can help you achieve and maintain a smooth, hair-free beautiful aspects. This is a convenient, low-Charge strategy to refresh your image, increase your confidence and enhance Your enjoyment of life everyday.
LAB REPORT 1st Experiment done in class Introduction: Agarose gel electrophoresis separates molecules by their size, shape, and charge. Biomolecules such as DNA, RNA and proteins, are some examples. Buffered samples such as glycerol and glucose are loaded into a gel. An electrical current is placed across the gel.
The Electrolysis of Copper Sulphate Aim Analyse and evaluate the quantity of Copper (Cu) metal deposited during the electrolysis of Copper Sulphate solution (CuSo4) using Copper electrodes, when certain variables were changed. Results Voltage across Concentration of solution electrode 0.5M 1.0M 2.0M 2 5.0 10.6 19.5 4 10.5 19.8 40.3 6 14.3 26.0 60.2 8 15.2 40.4 80.3 10 15.0 40.2 99.6 12 15.1 40.0 117.0 Analysing/Conclusion The input variables in this experiment are; concentration of the solution and the voltage across the electrodes. The outcome is the amount of copper gained (measured in grams) at the electrodes. By analyzing the graph, we can see the rapid increase of weight gained for the 2.0 molar concentration as the gradient is steeper.
If the distance between the two electrodes is smaller, the copper ions need less energy to flow from the anode to the cathode
The electrostatic precipitator (ESP) is a machine used in factories, to clean out the waste solid particle, for example ash from the exhaust gas, allowing clean exhaust gas exit through the chimney. The electrostatic precipitator functions by using first allow the exhaust gas with the waste solid particles pass through the Nozzle as shown in the diagram below. Then the exhaust gas passes through inlet gas distribution, which evenly distributes the gas as shown below in a turquoise color, and starts going through the Discharge electrodes and the collector plates, which is shown in the diagram red and blue respectively. The discharge electrodes, which are powered by high voltage direct current, ionize the gas along with the other solid waste particles negatively. The collector plates are also charged with high voltage electricity, but it is positively charged, therefore attracting the negatively charged solid particle, because oppositely charged particles attract. This allows the clean exhaust gas pass through the other end, while the solid waste particles are trapped in the collector plates. Eventually when there are enough solid waste particles collected on the collector plates, the collect plates shakes off the collected waste, where it drops to the bottom of the shaft as shown in the diagram as “Hopper”.
In this experiment three different equations were used and they are the Stoichiometry of Titration Reaction, Converting mL to L, and Calculating the Molarity of NaOH and HCl (Lab Guide pg. 142 and 143).
Electrolysis Investigation Planning In this investigation, I will assess how changing the electric current in the electrolysis of acidified water affects the rate at which hydrogen gas is produced. The solution to be electrolysed is made up using acid and water. It is of little consequence what acid is used however in this case I will use Sulphuric acid (H2SO4). When H2SO4 is put in water it is dissociated and forms ions: H2SO4 → 2H (2+) + SO4 (2-) Ions are also present from the water in the solution: H2O → H (+) + OH (-) During the electrolysis process, the positive hydrogen ions move towards the cathode and the negative hydroxide and sulphate ions move towards the anode.