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Electrolytes quizzlet
Short answers on electrolytes
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In procedure A, one must know what an electrolytes is, which is a substance that produces an electrically conducting solution when dissolved in a polar solvent, in this case water is the solvent. Based on the results of the experiment it is can be concluded that the sodium chloride solution best conduct electricity. This is due part by ions being separated into Na+ and Cl- ions from the original NaCl. In other words NaCl(s) becomes Na+ (aq) + Cl- (aq). In doing so allows electricity to flow in the solution. As for the pure/distilled water not conducting electricity it is because it is very filtered free of minerals. Essentially, distilled water lack ions to efficiently conduct electricity, this also applies to the pure substance of sodium chloride and sucrose which lack ions, atoms that have a net negative or positive charge. However, according the results the sucrose is slightly conductive, which may suggest a possible contamination in the solution. At the end it can be reasoned that because ions were made in the NaCl solution, ions contribute to the conductivity.
Based on the results salt water, sugar water, distilled water, and slightly isopropyl alcohol dissolved the Expo marker, while Oleic acid, slight Isopropyl alcohol dissolved the sharpie marker. All the solvents in the Expo trial have one thing in common: they are all polar and based on the saying "Like dissolves like" in this case Expo is polar therefore dissolved by polar solvents. This also applies to the sharpie, which is nonpolar because it does not dissolve in water which is polar. Especially Oleic acid, which is derived from oil and is polar. Therefore, it efficient dissolves the sharpie marker along with isopropyl alcohol which is also
Also, both their Ph level was 7 which mean that they are neutral and not acidic and reaction with iodine solution was exactly the same. Therefore, with all the experiments conducted and analyzed, icing sugar is the mystery substance. c) Q: Which properties, physical or chemical, were most useful in identifying the mystery powder? Explain your answer.
This experiment is used to determine the effect salt has on plant germination. In my scientific opinion, there will be a more dramatic increase of growth in the NaCl 0% out of the four solutions because it’s considered as distilled water which doesn’t increase or decrease the soils osmotic pressure, this way it’s a natural growth instead of being enhanced by NaCl different concentration levels.
* It was almost impossible to tell when the Alka-Seltzer tablet had dissolved, each time the experiment was done. This was a huge problem for the experiment as this could have totally caused problems to the experiment. A special type of detector apparatus, which bleeped when the correct amount of Alka-Seltzer tablet dissolved, could improve this, each time the experiment was done.
3. The beaker was filled with water and the metal was placed in the water.
The experiment started by labeling a piece of filter paper with my initials with the following A, B, C, oil, and H2O. I placed two drops of each unknown milk sample, vegetable oil, and H2O next to the labels on my filter paper and allow to air-dry. After these samples were dried, I placed the filter paper in a petri dish containing Sudan IV solution and stained the filter paper for one minute. I then used the forceps to remove the filter paper to the rinsing dish. Then, I rinsed the filter paper with water and collect the runoff in the dish. The last step, I placed the filter paper on the table and allowed it to
In the second experiment with the green color, I can safely conclude that the color green in this case is very soluble and we would need longer filter paper, perhaps more time to safely separate the different colors that make up the color green.
Methanol was the most polar among 3 alcohols used in this part, hence was soluble in water as both water and methanol were polar. However, methanol was partially soluble in hexane because the Van der Waals interaction between methanol
The experiment is aimed at giving a better understatement of osmosis process and the different conditions in which osmosis occurs.
The researcher conducting this experiment is trying to find out which salt- Epsom, table salt, and sea salt- will increase the boiling point of water the most. Sodium chloride is believed to increase the boiling point of water because when salt is suspended into the water, the sodium and chlorine ions leave the “salt crystals” and mix with the water molecules. (“Why does salt… raise boiling point of water?”, 2009).
== Refer to, Chemistry Lab #1 – What’s the substance? However, I changed some of procedures during my experiment, here is the changes I made in this experiment: * I only used the toothpick to place a small amount of each sample on a separate piece of paper, instead of the spatula.
A precipitation reaction can occur when two ionic compounds react and produce an insoluble solid. A precipitate is the result of this reaction. This experiment demonstrates how different compounds, react with each other; specifically relating to the solubility of the compounds involved. The independent variable, will be the changing of the various chemical solutions that were mixed in order to produce different results. Conversely the dependent variable will be the result of the independent variable, these include the precipitates formed, and the changes that can be observed after the experiment has been conducted. The controlled variable will be the measurement of ten droplets per test tube.
When a solution conducts electricity, the charge is carried by ions moving through a solution. Ions are atoms or small groups of atoms that have an electrical charge. Some ions have a negative charge and some have a positive charge. Pure water contains very few ions, so it does not conduct electricity very well. Not all substances are made up of ions. Some are made of uncharged particles called molecules. Sugar is such a substance. When sugar is dissolved in water, the solution does not conduct electricity, because there are no ions in the solution. That's why in Hands-on Squishy Circuits, the sugar PLAY-DOH did not produce electricity. The salt had ions in it to produce the electricity needed to make the LEDs light up.
For the solid sodium chloride, using distilled water will make it an aqueous solution. Just like before using red and blue litmus paper will only indicate that the sodium chloride is neutral. The same can be done for sodium carbonate since it is soluble in distilled water, making it easy to determine whether it is an acid or base when using litmus paper. In this case, sodium carbonate is a base so red litmus paper will turn blue when the solution of sodium carbonate is dripped on to it.
The electrodialysis setup consists of: an ED cell, a power DC, a brine tank, a feed tank, an electrode rinse tank, three centrifugal pumps (P = 84W, total head = 4.2 m) equipped each with a flowmeter and three valves to control feed flow rate. Fig. 2 shows a simplified diagram of the electrodialysis setup working in continuous mode.
In the experiment there are several possible ways of changing the electric current such as changing the voltage or the position of the electrodes within the electrolysis cell. However, it was found from preliminary work that the most effective way to change the current was to change the concentration of the acid solution. The preliminary work showed that the greater the concentration of the acid, the greater the current. Ohm's law states that R(resistance) =