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Solute Osmosis and Concentration
Solute Osmosis and Concentration
Sucrose solution concentration
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Recommended: Solute Osmosis and Concentration
The Effect of a Concentration of Water on the Mass of a Potato
Aim:
My aim is to find the percentage change of mass when a small piece of
potato is placed in to molar sucrose solution
Apparatus:
* Molar sucrose solution 0.0 - 0.5
* Potato
* Cutting board
* Knife
* Weighing machine
* Glass test tube
* Glass test tube holder
Plan: -
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My plan is too find the percentage change of mass of a small piece of
potato when placed in to molar sucrose solution by using osmosis.
Osmosis is explained below
Osmosis
Osmosis is the passage of water molecules from a region of their high
concentration to a region of their low concentration through a
partially permeable membrane. It is best regarded as a form of
diffusion in which only water molecules move. For example look at
Figure 2. The solute molecules are too large to pass through the pores
in the membrane, so the movement of water molecules can only achieve
equilibrium. Solution A has the higher concentration of water; so
there will be a net movement of water from A to B by osmosis. At
equilibrium there will be no further net movement of water. The
tendency of water molecules to move from one place to another is
measured as the water potential, represented by the symbol Y (greek
letter psi). water always moves from a region of higher pottential to
one lower water pottential. solute molecules reduce Y (in effect, they
dilute the water). The extent by which they lower Y is known as the
solute potential, given the symbol Ys.
Terms used
In 1988 the institute of biology recommended the use of the term water
potential to describe water movement through membranes. The two main
factors affecting the water potential of plant cells are solute
concentration and the pressure generated enters and inflates plant
For the sample calculations, let’s use the marshmallow as an example. Its initial mass was 0.66 grams and its final mass was 0.36 grams. To calculate the amount burned, subtract 0.36 from 0.66 to get 0.30 grams. (Mass burned = mi- mf). To find the marshmallow’s change in temperature, use the formula (ΔT =
One of the best methods for determining mass in chemistry is gravimetric analysis (Lab Handout). It is essentially using the the mass of the product to figure out the original mass that we are looking for. Thus the purpose of our experiment was to compare the final mass in our reaction to the initial mass and determine the change in mass.
If we say that the right hand side in picture 1 is the potato, and the
If the concentration of one side of the membrane is greater than the molecules will travel from the higher to lower concentration. Eventually there will be a dynamic equilibrium and there will be no net movement of molecules from one side to the other. Osmosis is the diffusion of water. Like diffusion, the water moves from a region of higher water potential to a region of lower water potential.
* Note the mass down in the table at the end of the first page.
find the rate I have to find the mass change in 1 hour, and I will
Conclusion: Finally, water molecules are moved from high concentration to low concentration Based on the data collected and the results of the experiment, the hypothesis was correct.
A good example would be the experiments with the concentrations of 20% to 60% concentration results to show the change. In the 20% concentration I noticed a decrease in the percentage change in mass for the experiment the percentage was _____ while for the concentration of sucrose 60% the change was _____ we can see that the percentage change in mass is decreasing thus we can conclude that the difference of the initial from the final and as it gets greater that means the mass of the potato changed massively.
Conclusions: There is a pattern on the graph, and data table, which shows that as the concentration of the sucrose solution increases, the potato's percentage change in mass decreases.
I have chosen to look at the effect of the weight applied, as it is a
= == In my investigation to find out how salt solution concentration affect the mass of potatoes, I will investigate how much the mass of a potato changes if I leave it in a beaker of water with a specified salt concentration for half an hour. I will change the salt concentration after each experiment. Background Knowledge --------------------
However, in this diagram we see that osmosis has been taking place for a short while, because water molecules have started to diffuse to the right, across the membrane, so that there are now many present on the right side of the membrane, and a few sugar molecules are starting to diffuse across the membrane in the opposite direction, to the left side of the membrane as we see it. Through moving from an area of lots of free water molecules, to an
the gain or loss of water when samples of the tissue are placed in a
Weigh out two 0.100 g. samples of the product and put each into a test
v = (0.80 kg × 12.0 ms-1) + (0.40 kg × -8.0 ms-1) / (0.80 kg + 0.40kg)