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An essay on biosensors
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Purpose: To identify an unknown microorganism by performing a series of biochemical tests on a pure bacterial culture. Materials and Methods: 1. Carbohydrate Utilization: Two culture tubes, phenol red lactose broth and phenol red sucrose broth, were each inoculated with one loopful of organism 3 from a broth culture. The broths were incubated at 37°C. After 24-48 hours, the mediums were examined. A positive test result is indicated by a change from the red broth to a yellow broth. A change from red broth to orange broth, or no change in color, is indicated as a negative result. A gas bubble produced in the Durham tube is indicated as a positive result for gas. A negative result for gas is indicated by no gas in the Durham tube. …show more content…
2. Indole Production: A 1% tryptone broth was inoculated with one loopful of organism 3 from the broth culture. The tube was incubated at 37°C for 24-48 hours. After adding 5 drops of Kovac’s reagent, a yellow/green or red ring will appear at the top of the broth in the tube. The yellow/green ring around the top indicates a negative test result, while a red ring indicates a positive test result. 3. Urea Hydrolysis: One tube of urea broth was inoculated with one loopful of organism 3 from the broth culture. Before the experiment, the broth is a yellow color. The urea broth was incubated at 37°C for 24-48 hours. A color change from yellow to red indicates a positive test result. A change from yellow to orange, or no color change at all, indicates a negative result. 4. Starch Hydrolysis: A starch agar plate was inoculated with one loopful of organism 3 from the culture broth. The agar was inoculated with one straight line in the middle of the plate. The plate was incubated at 37°C for 24-48 hours. After incubation, iodine is added to cover the plate. A clear zone formed around the growth on the plate is considered a positive result. No clear zone around the growth is considered a negative test result. 5. Sulfide Production: A disposable inoculating needle was rolled in organism 3 on the slant growth. The needle was inserted straight into one tube of SIM media, and pulled straight out. The tube was incubated at 37°C for 24-48 hours. A positive test result will show black precipitate in the medium. A negative test result will show very little or no black precipitate in the medium. 6. Motility: A disposable inoculating needle was rolled in organism 3 on the slant growth. The needle was inserted into one tube of motility test medium. The tube was incubated at 37°C for 24-48 hours. Abundant red growth in the tube indicates a positive result for motility. Red growth strictly where the needle was inoculated results in a negative result for motility. 7. Casein Hydrolysis: One skim milk agar plate was inoculated with one loopful of organism 3 in a straight line across the plate. The plate was incubated at 37°C for 24-48 hours. A clearing around the growth on the plate indicated a positive test result. No clearing around the growth is a negative test result. 8. Catalase Production: One nutrient agar plate was streaked with organism 3. The plate was incubated at 37°C for 24-48 hours. After incubation, 3% hydrogen peroxide is dropped onto a single colony of bacteria. The formation of bubbles indicates a positive test result, while no formation of bubbles indicates a negative test result. Results: 1. Carbohydrate Utilization: In the phenol red lactose broth, the color changed from red to yellow, indicating a positive test result. No gas bubbles were seen in the Durham tube, indicating a negative test result. In the phenol red sucrose broth, the color did not change at all and there was no gas in the Durham tube. Both of these results are negative test results. 2. Indole Production: When Kovac’s reagent was added to the 1% tryptone broth, the color of the ring at the top of the tube was green. This is a negative test result. 3. Urea Hydrolysis: In the urea broth, the color started as yellow when the experiment started. After incubation, the color was still yellow. This is a negative test result. 4. Starch Hydrolysis: After incubation, the starch agar plate was covered in iodine. There was no clear zone around the growth on the plate, and no color change. This means the test result is negative. 5. Sulfide Production: The SIM media did not show any growth of organism 3. There was no black color in the medium. This is a negative test result. 6. Motility: Organism 3 did move a little bit in the motility broth. It only moved in one direction, slightly away from the space where the needle was inoculated. This did not move enough to be considered motile, resulting in a negative test. 7.
Casein Hydrolysis: The skim milk agar plate did not have any clearing around the growth. This is a negative test result. 8. Catalase Production: When 3% hydrogen peroxide was added to an isolated colony, no bubbles formed. This is a negative test result. Discussion: 1. Carbohydrate Utilization: The test result for the phenol red lactose broth was positive for acid and negative for gas. The positive result for the acid means that the organism is able to ferment the particular sugar lactose. The Durham tube did have gas in it which means the organism produced gas in the lactose broth. The rest result for the phenol red sucrose broth was negative for both acid and gas. This means the organism was not able to ferment in sucrose. The organism was also not able to produce gas in the sucrose broth. 2. Indole Production: The result for this test was negative. This means the organism does not produce tryptophanase. The organism is not able to split the amino acid tryptophan into indole and pyruvic acid. There was no indole produced from the breakdown of tryptophan. 3. Urea Hydrolysis: This test result was negative. There was no accumulation of sufficient ammonia from the hydrolysis of urea. An alkaline environment was not created by organism
3. 4. Starch Hydrolysis: The result for starch hydrolysis was negative. This means that after the iodine was covering the bacteria, there was no clearing around the growth. This bacteria does not produce the enzyme amylase. The starch is not broken down into single units of glucose that can be used in cellular respiration or energy production. 5. Sulfide Production: The negative test result for sulfide production means that no hydrogen sulfide was produced. There was no reaction with ferrous salts to form black metal sulfides, which indicates a positive test result. 6. Motility: The negative test result for motility shows that organism 3 is not a motile organism. Organism 3 does not have any flagellum on them. Flagella help the bacteria move toward nutrients and other beneficial elements and move away from toxic substances and environments. 7. Casein Hydrolysis: The negative test result for this test shows that organism 3 was not able to produce the extracellular enzyme caseinase, which breaks down casein into smaller soluble units. 8. Catalase Production: The result for the catalase production is negative. A negative test result means that catalase was not produced by organism 3. The organism is anaerobic because it did not produce bubbles to protect itself from the hydrogen peroxide added to it. Conclusion: The unknown organism number 3 appears to be Staphylococcus epi. The table of positive and negative results that we made had two columns of same results as my unknown bacteria. The gram stains were also the same for Enterococcus faecalis and Staphylococcus epi. After researching both gram stains, the Staphylococcus epi gram stain was most similar to the way organism 3 looked like under the microscope. Enterococcus faecalis had some pink bacteria stained behind the gram positive cells. This did not appear in my gram stain of organism 3. Therefore, I have concluded that organism 3 must be Staphylococcus epi.
I identified the genus and species of an unknown bacterial culture, #16, and I applied the following knowledge of morphologic, cultural and metabolic characteristics of the unknown microorganism according to the laboratory manual as well as my class notes and power point print outs. I was given an incubated agar slant labeled #16 and a rack of different tests to either examine or perform myself; the tests are as follows: Gram Stain; Nutrient Gelatin Test; Carbohydrate Fermentation; Dextrose, Lactose and Sucrose; IMVIC tests; Citrate, Indole, Mythel-Red and Vogues Proskauer test; as well as a Urease and TSI Test.
One bacterium was gram negative. It underwent four different tests. These tests were the EMB test (Eosin Mehylene Blue), the Sulfur Indole Motility (SIM) test, the Urease test, and the Simmon’s Citrate Utilization test. The EMB test checks for a bacteria’s ability to ferment lactose. This test is accomplished by placing the bacteria on Eosin Methylene Blue agar. The agar is selective for gram negative bacteria and those bacteria that can ferment lactose will have colored growth, usually a metallic green sheen.
Streak plate technique was used to isolate pure culture for each bacteria (2). The Gram stain was used to determine Gram reaction and morphology of each bacteria (2) Selective and differential media such as, salt agar, MacConkey agar and blood agar were used for bacterial identification (2). Gelatin deeps were inoculated to detect production of gelatinase (2). Starch Agar plate were inoculated to detect amylase (2). Ocular reticle used to determine bacteria size (2). Motility deeps were inoculated to detect motility on bacteria (2). Thioglycollate broth used to determine oxygen requirements (2). Carbohydrate fermentation
They can be found anywhere and identifying them becomes crucial to understanding their characteristics and their effects on other living things, especially humans. Biochemical testing helps us identify the microorganism present with great accuracy. The tests used in this experiment are rudimentary but are fundamental starting points for tests used in medical labs and helps students attain a better understanding of how tests are conducted in a real lab setting. The first step in this process is to use gram-staining technique to narrow down the unknown bacteria into one of the two big domains; gram-negative and gram-positive. Once the gram type is identified, biochemical tests are conducted to narrow down the specific bacterial species.
The unknown substance is probably a carbohydrate because it tested positive for starch which is a polysaccharide. This reaction also had very similar results as the Lugol’s test for potatoes which is a polysaccharide. Although the colors from the test for potatoes were not the same colors as the test for the unknown; the Biuret test had a slight color change and the Lugol’s test had a dramatic color change for both the unknown and potatoes. I am sure that the unknown was a starch, but the Benedict’s test for sugar was positive for the potatoes while the Benedict’s test for the unknown didn’t have a color change. The unknown probably did not have a color change for the Benedict’s test simply because there were not enough sugar present in the unknown for it to test positive. The Sudan IV Test for Lipids did not test positive for the unknown nor the potatoes because there isn’t a trace of lipids in starch. Based on my results, the unknown has a little protein, a lot of starch and no traces of lipids or
I was given unknown organism #14, in order to find out what organism I had, I had to perform several different biochemical tests to identify it. Starting with the Gram stain test, which is performed to differentiate Gram-positive and Gram-negative cells. After staining, when observed through the microscope Gram-positive cells are a purple color with thick peptidoglycan cell walls. Gram-negative cells are a pinkish/red color with thinner cell walls. (handout G. s.) My organism was observed to be pinkish rod shaped meaning it is Gram-negative bacteria.
While the tube for specimen Cb turned a tannish white in the lower half of the tube while the top stayed the lavender inoculated tube color. Do to this evidence I determined that both specimens Ca and Cb cannot use the process Casein hydrolysis or Casein coagulation due to lack of soft or firm curds in both tubes. Since there was no casein curds formed, I concluded that specimens Ca and Cb also cannot perform the process of proteolysis. My conclusion is supported by the fact that there was no clearing of the medium. I have also determine that neither of my organisms can make the enzymes rennin, proteolytic or even proteases. I know my specimens cannot produce proteases due to the fact that there was no blue coloring in the tubes which means that the byproduct Ammonia was not produced to increase the pH. Since neither of my specimens can make these enzymes, I concluded that my specimens cannot break down lactose or casein. Although I did learn that specimen Cb can reduce litmus due to the evidence that the lower part of the tube turned a tannish white color with a purple ring at the top. This color change from a purple to a white means that the litmus was reduced turning it clear and leaving the white of the milk to show. Finally I know that specimen Ca cannot reduce litmus due to the fact that the tube had no change in
The purpose of this experiment was to discover the specificity of the enzyme lactase to a spec...
The purpose of the study is to identify an unknown microorganism using multiple microbiology lab techniques. Through this process I will gain knowledge on how to perform these techniques as well as the importance of these tests on identifying unknown microorganisms. This is significant as the goal of this course is to familiarize ourselves with the common microbiology tests as well as the microorganisms we encounter in our daily activities.
An error that occurred in the experiment was during the ceric nitrate test because solution 4 should have produced a color change. During a base hydrolysis of aspartame, aspartic acid, phenylalanine and methanol are produced, therefore the ceric nitrate test should have been a positive for alcohol. A reason that this could have shown a negative result is because methanol is a volatile substance and it could have evaporated out, which would have caused a negative ceric nitrate test
This lab attempted to find the rate at which Carbon dioxide is produced when five different test solutions: glycine, sucrose, galactose, water, and glucose were separately mixed with a yeast solution to produce fermentation, a process cells undergo. Fermentation is a major way by which a living cell can obtain energy. By measuring the carbon dioxide released by the test solutions, it could be determined which food source allows a living cell to obtain energy. The focus of the research was to determine which test solution would release the Carbon Dioxide by-product the quickest, by the addition of the yeast solution. The best results came from galactose, which produced .170 ml/minute of carbon dioxide. Followed by glucose, this produced .014 ml/minute; finally, sucrose which produced .012ml/minute of Carbon Dioxide. The test solutions water and glycine did not release Carbon Dioxide because they were not a food source for yeast. The results suggest that sugars are very good energy sources for a cell where amino acid, Glycine, is not.
In the experiment, five periods are done to accomplish the goal of identification of the unknown microorganism. The first period aims to isolate the genomic DNA from the unknown microorganism using a
...ed that the liver was able to detoxify sulfate properly. The last inorganic constituent tested was calcium, which was done by adding equal amounts of urine and Sulkowitch’s reagent. A large amount of white precipitate was form due to the dietary consumption of the subject which can be that milk was consumed daily. Finally, the last tested was the abnormal constituents of urine. When testing for glucose the results were negative because the reagent was not reduced meaning that it did not turned greenish or red-brown color. The presence of glucose indicates diabetes mellitus which is a metabolic disorder that is caused by the usage of defective carbohydrate. Then when testing for albumin and globulin the results showed that a large amount of protein was present, which means that the subject had an abnormal leakiness or severe damage of the glomerular membrane or both.
It was observed that the percentage titratable acidity increased, but not as higher as the value of treatment 1, because this treatment has already undergone alcoholic fermentation which was carried out by the added yeast, Saccharomyces cerevisiae. In this treatment, sugar was used as the substrate, and yeast was used to produced alcohol and carbon dioxide. Alcohol hinders the growth and survival of the unwanted microorganisms, since it denatures their membrane. In addition, alcoholic fermentation is used in making alcoholic beverages such as beer and wine. According to Rahman (2007), with respect to oxygen supply, this treatment undergone anaerobic fermentation because of the dissimilation of carbohydrate happened in which oxygen is not involved, but rather other substances, aldehydes and pyruvic acid that served as a hydrogen acceptor. On the other hand, increase in the percentage titratable acidity happened due to the molecules of carbon dioxide which has already reacted with the water, forming carbonic acid that made the mixture more acidic compared to the treatment 1. This happened since carbonic acid is a weak acid that causes a slight drop in pH, thus, making the mixture more acidic. Nevertheless, carbon dioxide alone is not acidic (Pederson,
...he results of the yogurt production after 3 days are as follows: the yogurt has a semi-solid texture, acidic smell, and a sour taste indicating that Lactic acid production took place. The wine production results after the same amount of time was as follows: the wine smells slightly of alcohol, the amount of liquid decreased, and some bubbling is still present; the balloon is currently inflated and producing carbon dioxide. Based on these results the ethanol fermentation was also successful. During both of these experiments fermentation took place, in the case of the yogurt the Lactic acid gave the yogurt a tart taste and smell, and in the Ethanol fermentation the wine smelled of alcohol and produced carbon dioxide indicated by the air in the balloon. In conclusion, NADH was oxidized and Lactic acid and ethanol were produced in both experiments through fermentation.