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Factors affecting the resistance of a wire
Factors affecting the resistance of a wire
Factors affecting the resistance of a wire
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Recommended: Factors affecting the resistance of a wire
Measuring the Resistivity of a Wire
Aim
The aim of this experiment is to find out how the area of the cross
section of the wire affects the resistance and also to find out the
resistivity of the wire having found the resistance over a certain
length and using a certain cross sectional area. I will also
experiment to see how the length of the wire affects the resistance.
Plan
The first thing that I will do is to set up the apparatus as shown
below.
A,V
Except for the experiment where I alter the length, I will keep the
length of the wire constant throughout the experiments and only change
the diameter of the wire. For each width I will record the p.d. and
current displayed on the voltmeter and ammeter. I will then use these
values to calculate the resistance of the wire at that length using
the formula:
[IMAGE]V = IR or R = V (where V = p.d., I = Current, and R =
Resistance)
I
I will then find the cross sectional area of the wire. To do this I
will find the diameter of the wire using a micrometer. Then I will
find the area of the cross section by using the formula:
Area = πr² (where A = Area of cross section, π = pi, and r = radius)
Once I have this value I will be able to calculate the resistivity of
the wire by substituting the values into this formula:
R=rl or r= RA (where A = Area of cross section, R = Resistance, l =
[IMAGE][IMAGE] A l length, and r= resistivity)
I will repeat this for all of the different diameters that I will test
but will remember to keep the length of the wire the same throughout.
The apparatus that I will use for this experiment are listed below:
· Power supply - This will be 3V of power and will be used to power
the circuit so that I can measure the resistance of the wire.
I also decided to use a wooden block to keep hold of the wire, because
A = cross sectional area of the connecting rod. l = length of the connecting rod.
2) In the geometric figure the vertex V = 6 and the face, F = 6. Find the edge of the geometric figure using the formula.
This shows that there is a difference of 2cm between A and B, and B
5. Put the stirring wire through the second hole of the stopper. Insert the stopper, thermometer, and wire into the test tube. Make sure that the thermometer bulb is below the surface of the solution.
PREDICTION: I think that the shape with the area of 6 cm2 will have 61
surface area of the potato chip, first I will put it in the beaker as
as the “r-value” and “r” can be any value between -1 and +1. It can be
* Surface Area - This will not affect any of my results, as we are
If I were using a cut out of length 1cm, the equation for this would
This is know as resistivity. The factors I can investigate are : Ÿ Temperature Ÿ Length Ÿ Cross-sectional area/width Ÿ Material (resistivity) The factor I shall investigate is the length of a wire. Background Knowledge Resistance is when electrons travelling through the wire are impeded by the atoms within the wire. Since the electrons are charge carriers when they collide with the atoms in the wire less pass through.
-Voltmeter -Variable resistor -Power Supply -Various diameters of wire -Crocodile clips -Metre ruler [ IMAGE] Diagram:.. Secondary Source - (Obtained in A-level PHYSICS by Roger Muncaster). Page 536 - "The 'Page The electrical resistivity of a material is defined by R = L / A Where R = Resistance of some conductor(Î).
Volume's Effect on a Copper Sulphate Solution We are trying to find out if the current though a copper sulphate solutions volume is increased. To find this information out I shall perform an experiment using the following equipment; · 1 power pack · 1 beaker · 2 carbon rods for anode and cathode · 1 ammeter · 1 measuring cylinder · 2 crocodile clip wirers I shall also be using 60cm3 volume of copper sulphate in my preliminary results to decide upon the concentration of copper sulphate and the voltage I shall use. The following diagrams show the step by step process in which I will do my experiment; [IMAGE] [IMAGE] [IMAGE] [IMAGE] I will take 10 readings from 10cm3 to 100cm3. I will repeat my experiment to give my experiment a fair average. I will keep the power pack the beaker the carbon rods the crocodile clips the ammeter the concentration of copper sulphate and the measuring cylinder the same each time I do the experiment this experiment.
Inversely, to decrease I, R must increase. The value of R depends on how easy it is for the electric charge to pass through the conductor. Therefore to decrease R, the passage must be made easier and to
The ratio for length to width of rectangles is 1.61803398874989484820. The numeric value is called “phi”.