Roble Sami. Punnet who task. 1.Answer: ¾ or 75% A a A AA Aa a Aa aa 2.Brown eyes are dominant (B) and blue eyes are recessive (b). Since the man is brown eyed, here genotype could be either BB or Bb, because in both cases the B would be dominant over the b. 3. ½ or 50% B b b Bb bb b Bb bb 4.The parent's genotype must be Ww and Ww, with white being the dominant gene. This will give a result of ¾ white, and ¼ black White is dominant = W Black is recessive = w Parents = homozygous …show more content…
The probability that the next offspring will be black is ¼ or 25%. 5.Use a test-cross. Mate the unknown fly to a known homozygous recessive. Think about the results if the fly was heterozygous vs. if it were homozygous dominant. 6.R = red, r = yellow T = tall, t = short homozygous red, homozygous short parent is …show more content…
Phenotypes red tall, red short, red tall, and red short - in 1:1:1:1 ratio, The phenotype ratio is 1/2 red tall: 1/2 red short. 7. G.pig1 + G.pig2 BbSs + bbss (B=black,b=white) (S=short,s=long hair) G.pig1-gametes=4types 1.BS 2.Bs 3.bS 4.bs G.pig2- gamete =1 type A.bs F1CROSS =1A, 2A, 3A, 4A. i.e BbSs,Bbss,bbSs,bbss.(black coat- short hair,black coat- long hair,white coat- short hair,white coat-long hair) 8..this is a simple double cross. a)parents have tall length and round pods. b)possible phenotypes 1.tall+round pods 9/16 probability 2.tall+wrinkled pods 3/16 " 3.short+round pods 3/16 " 4.short+wrinkled pods 1/16
In order to figure out the genes responsible, there are several other factors that must be determined. These factors include the number of genes involved, if each gene is x-linked or autosomal, if the mutant or wild-type allele for each is dominant, and if genes are linked or on different chromosomes. Proposed crosses include reciprocal crosses between the pure-breeding mutants of strains A and B with the wild-type will help determine if the genes or sex-linked or autosomal, in addition to which alleles are dominant (8). Another proposed cross includes complementation crosses between pure-breading mutants from strains A and B to determine if one or two genes are involved (8). Furthermore, testcrosses between F1 progeny and pure-breeding recessive mutants from strains A and B, which will help determine if genes are linked on the chromosome or if they assort independently (8). These proposed crosses are shown in the attached
revealed that three of the fourteen samples were were homozygous while the other eleven were
The idea of the project was to experiment breeding Drosophila Melanogaster (fruit fly) to figure out if certain genes of that species were sex linked or not (autosomal). A mono-hybrid cross and di-hybrid cross was performed. For the mono-hybrid cross, white eyed female and red eyed male were placed in one vial for them to reproduce. For the di-hybrid cross, red eyed and normal winged flies and sepia eyed and vestigial winged flies were placed in their vial to reproduce. In the mono-hybrid cross the results expected were within a 1:1:1:1 ratio. Expected results similar to the expected desired null hypothesis proposed with what the F1 parental generation breeds. The potential results would have had to have been within the ratios of 9:3:3:1. The results were clear and allowed the null hypothesis to be correct. The white eyed gene in the fruit flies is sex linked. Sepia eyes and vestigial wings are not sex linked and are examples of independent assortment.
In this experiment, Mendelain Models are observed. The purpose of the experiment is to understand how traits are passed from one generation to the other as well as understanding the difference between sex linked and autosomal genes. One particular trait that is observed in this experiment is when a fly is lacking wings, also known as an apterous mutation. In this experiment, we will determine whether this mutation is carried on an autosomal chromosome or on a sex chromosome. The data for this experiment will be determined statistically with the aid of a chi-square. If the trait is autosomal, then it will be able to be passed to the next generation on an autosomal chromosome, meaning that there should be an equal amount of male and
3. Possible genotypes... Aunt 1 X --X, Aunt #2 X-- X, Aunt Dee X-- X, Michalla X-- X, Augusto X-- Y and Lorenzo X-- Y
An individual can be homozygous dominant (two dominant alleles, AA), homozygous recessive (two recessive alleles, aa), or heterozygous (one dominant and one recessive allele, Aa). There were two particular crosses that took place in this experiment. The first cross-performed was Ebony Bodies versus Vestigle Wings, where Long wings are dominant over short wings and normal bodies are dominant over black bodies. The other cross that was performed was White versus Wild where red eyes in fruit flies are dominant over white eyes. The purpose of the first experiment, Ebony vs. Vestigle was to see how many of the offspring had normal bodies and normal wings, normal bodies and vestigle wings, ebony bodies and normal wings, and ebony body and vestigle wings.
Anthocyanin is a purple colored pigment in plants that protect tissue from stressful light conditions (Glover and Martin 2012). This experiment utilized monohybrid crosses of the Wisconsin Fast Plant variety of B. rapa with the F_1 generation having one dominant allele for anthocyanin (ANL) and one recessive allele (anl) (Kinds Plants 2014), to complete their life cycle and produce offspring that were observed for their phenotype. By utilizing the genotype of each parent a prediction for the outcome of these genetic crosses was formulated with a Punnett square (Brooker et al. 2014). Since two alleles need to be existent for a recessive trait to be conveyed, and only one allele for a dominant trait (Morgan and Carter 2008), the offspri...
A genetic family history assessment contains information about family structure and relationships. A typical nurse will use a three-generation family pedigree to gather the information. By doing so, nurses can be aware of which family members are at risk for disorders from a genetic component. Therefore, they can be provided with lifestyle advice, recommendations, and referrals to appropriate specialists (Kaakinen, Coehlo, Steele, Tabacco & Hanson, 2015). A genetic family history assessment will be provided about my family.
Lewis, Ricki, (2014), Human Genetics, 11th Edition, Chapter 12. Gene Mutation. [VitalSource Bookshelf Online]. Retrieved from
Flies that began mating on hawthorns now have a population that mate on apples. 2. What is the difference between a.. What is the difference between polygenic inheritance and pleiotropy? Polygenic:
According to biological traits, racial categories are considered to be visible genetic traits which are face structures, shape of the body, and skin color. However, certain differences and
middle of paper ... ... avour of "purity of the race" idea, but they understand how it worked. Blond hair and blue eyes are recessive genes. Two brown-eyed people can give birth to a blue-eyed child, but two blue-eyed people cannot give birth to a brown-eyed child. Dark skin and dark hair are also dominant genes, so because of evolution, it must mean that the ancestors of humanity had dominant genes.
After completing my family genogram, I was able to notice the history of a couple of patterns of fusion in particular. One of the relational patterns that stood out was emotional abuse which for the sake of this assignment I have only traced it back three generations, starting with my paternal grandfather Marciano, who endured the aftermath of the WWII and who conceived out of wedlock (COW) from Spanish and Mestizo parents and who married a woman Fidelina, of Chinese and Indian origin, born in El Salvador like him. Based on anecdotal accounts, Marciano was particularly emotionally abusive towards Rosa, my mother, who is also the first born of the couple and COW. Marciano had very high standards of beauty and intellect, which often triggered name calling, insults, and other forms of humiliation aimed towards my mother, causing her to feel belittled and resent his treatment towards her.
Heterozygote superiority. (n.d.). In World of biology. Retrieved from Gale Science in Context database. (Accession No. CV2431500311)
In the photo above is a family with very good genetics and we can see tha...