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State the application of IR spectroscopy
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Recommended: State the application of IR spectroscopy
Asha Kurup
April 3rd, 2014
IR Spectroscopy Assignment
A. What is spectroscopy and how does it work?
Spectroscopy is a term for analyzing spectra. The spectra may be visible light, infrared, ultraviolet, X-ray, and other types1. When a beam of light hits a triangular prism, it is separated into its components (ROYGBIV).
Figure 1: Components of Light
Spectroscopy is measured using a spectrophotometer. A beam of light is first pointed towards the spectrophotometer. The beam of light then strikes a part of the spectrophotometer called the diffraction grating. The diffraction grating works similar to the prism shown above. It separates the light into its component wavelengths by rotating so that only a specific wavelength will reach a part of the spectrophotometer called the exit slit. On the other end of the exit slit there is a sample located in a test tube as well as a detector. After the wavelength passes through the sample, the detector measures the transmittance and absorption of the sample. The transmittance is the amount of light that was able to pass through the sample and reach the detector, and the absorption is the amount of light that was absorbed by the sample. The detector converts the measure of transmittance into s digital display, such as a graph.
B. What purpose does it serve in the industry?
Spectroscopy can help identify elements and compounds and elucidate the atomic and molecular structure by measuring the radiant energy absorbed or emitted by a substance at characteristic wavelengths of the electromagnetic spectrum on excitation by an external energy source. UV-Vis Spectroscopy is a technique useful for identification of organic and inorganic species and can be used for identification (qualitiative ana...
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...either sp3 hybridization or an alkyl group. By looking at the chemical structure, we can see that two methyl groups are present, and this peak confirms this.
There are no peaks in zone 3, therefore there are no alkyl or nitrile groups present. There are also no peaks in zone 4, indicating that there are no ketone, ester, or carboxylic acid functional groups present.
In zone 5, there are two peaks. One peak is at 1600cm-1, and the other is between 1500 and 1450cm-1. These two peaks indicate that a benzene ring is present in the chemical structure of the compound.
The next part of the graph is the fingerprint region. In the fingerprint region there are two important peaks. The first of these appears around 750cm-1, and the second at 690cm-1. These two peaks indicate that the benzene ring that we discovered present in the structure is a monosubstituted benzene ring.
...icted α-methyl-2-naphthalenemethanol. Probably the most obvious clue that corresponded to this secondary alcohol was the seven integrated hydrogens within the aromatic region of 7.5-7.9 ppm. This compound was the only one that had seven hydrogens belonging to naphthalene. The other two secondary alcohols 3-methoxy-α-methylbenzyl alcohol and 4-bromo-α-methylbenzyl alcohol have only four aromatic hydrogens.
Absorbance was defined as: log I_o/I where I_o is incident light and I is the transmitted light. Fluorescence emission spectrum is different from fluorescence excitation spectrum because it records different wavelengths of chemical s...
...e 3. Both letters A and B within the structure of trans-9-(2-phenylethenyl) anthracene, that make up the alkene, have a chemical shift between 5-6 ppm and both produce doublets because it has 1 adjacent hydrogen and according to the N + 1 rule that states the number of hydrogens in the adjacent carbon plus 1 provides the splitting pattern and the number of peaks in the split signal, which in this case is a doublet.1 Letters C and D that consist of the aromatic rings, both are multiplets, and have a chemical shift between 7-8 ppm. 1H NMR could be used to differentiate between cis and trans isomers of the product due to J-coupling. When this occurs, trans coupling will be between 11 and 19 Hz and cis coupling will be between 5 and 14 Hz, showing that cis has a slightly lowered coupling constant than trans, and therefore have their respective positions in a product. 2
The IR spectrum that was obtained of the white crystals showed several functional groups present in the molecule. The spectrum shows weak sharp peak at 2865 to 2964 cm-1, which is often associated with C-H, sp3 hybridised, stretching in the molecule, peaks in this region often represent a methyl group or CH2 groups. There are also peaks at 1369 cm-1, which is associated with CH3 stretching. There is also C=O stretching at 1767 cm-1, which is a strong peak due to the large dipole created via the large difference in electronegativity of the carbon and the oxygen atom. An anhydride C-O resonates between 1000 and 1300 cm-1 it is a at least two bands. The peak is present in the 13C NMR at 1269 and 1299 cm-1 it is of medium intensity.
A weak peak was at a position between 1600-1620 cm-1 can also be seem in the IR, which was likely to be aromatic C=C functional group that was from two benzene rings attached to alkynes. On the other hand, the IR spectrum of the experimental diphenylacetylene resulted in 4 peaks. The first peak was strong and broad at the position of 3359.26 cm-1, which was most likely to be OH bond. The OH bond appeared in the spectrum because of the residue left from ethanol that was used to clean the product at the end of recrystallization process. It might also be from the water that was trapped in the crystal since the solution was put in ice bath during the recrystallization process. The second peak was weak, but sharp. It was at the position of 3062.93 cm-1, which indicated that C-H (sp2) was presence in the compound. The group was likely from the C-H bonds in the benzene ring attached to the alkyne. The remaining peaks were weak and at positions of 1637.48 and 1599.15 cm-1, respectively. This showed that the compound had aromatic C=C function groups, which was from the benzene rings. Overall, by looking at the functional groups presented in the compound, one can assume that the compound consisted of diphenylacetelene and ethanol or
The C-H (sp3) hydrogens from our product displayed at wavelength 2959 cm-1 correlates to the methyl groups located on the ends of isopentyl acetate4. A really prominent, strong peak located at 1742 cm-1 shows that a C=O ester stretch is located in the product, along with at 1244 cm-1 the spectrum shows a strong peak representing the C(=O)-O stretch that is crucial to the structure of isopentyl acetate. Shown in my IR spectrum is a weak O-H (H-bonded) peak at 3464 cm-1 which shows that I have an impurity of isopentyl alcohol in my product. Isopentyl alcohol has similar boiling points and density as my product so the impurity could have easily boiled out with the isopentyl acetate during distillation. The isopentyl alcohol was also present in my 1H-NMR spectrum backing up the impurity peak at 3464
1972 fluid mosaic model. Lipids are commonly recognized as fats, oils, wax, etc. There are three
If the elimination happens with either protons in the terminal methyl group, the resultant product is 1-butene, a Hoffman product (monosubstituted alkene). In contrast, elimination of either -hydrogens by the conjugate base of sulfuric acid (HSO4) on the methylene group leads to an alkene that is dissubstituted. Either the cis- or trans-2-butene can form depending on which hydrogen is deprotonated. These are the Saytzeff products since they are the most popular ones. In this case, the trans-alkene is the most stable, thus one should see the greatest area for the second peak when analyzing the gaseous products under gas chromatography.
After performing the second TLC analysis (Figure 4), it was apparent that the product had purified because of the separation from the starting spot, unlike Figure 3. In addition, there was only spot that could be seen on the final TLC, indicating that only one isomer formed. Since (E,E) is the more stable isomer due to a less steric hindrance relative to the (E,Z) isomer, it can be inferred that (E,E) 1,4-Diphenyl-1,3-butadiene was the sole product. The proton NMR also confirmed that only (E,E) 1,4-Diphenyl-1,3-butadiene formed; based on literature values, the (E,E) isomer has peaks between 6.6-7.0 ppm for vinyl protons and 7.2-7.5 ppm for the phenyl protons. Likewise, the (E,Z) isomer has vinyl proton peaks at 6.2-6.5 ppm and 6.7-6.9 ppm in addition to the phenyl protons. The H NMR in Figure 5 shows multiplets only after 6.5 ppm, again confirming that only (E,E) 1,4-Diphenyl-1,3-butadiene formed. In addition, the coupling constant J of the (E,E) isomer is around 14-15 Hz, while for the (E,Z) isomer it is 11-12 Hz. Based on the NMR in Figure 5, the coupling constant is 15.15 Hz, complementing the production of (E,E)
An oscilloscope is a laboratory instrument that commonly used to display and analyze the waveform of electronic signals. This device draws a graph of signal voltage as a function of time. Oscilloscope usually have two-dimensional graph which electrical potential differences represent by Y-axis (vertical) and time represent by X-axis (horizontal). With positive values going upward and negative values going downward (Ask.com, 2014). In any oscilloscope, the horizontal sweep is measured in seconds per division (s/div), milliseconds per division (ms/div), microseconds per division (s/div), or nanoseconds per division (ns/div). The vertical deflection is measured in volts per division (V/div), millivolts per division (mV/div), or microvolts per division (µV/div).
Fig 1: Applications of single molecule spectroscopy in solving scientific problems in Physics, Chemistry and Biology
To understand this week’s experiment one must first understand what a spectroscope is and what it does. With this understanding in hand, one would gain a deeper appreciation for this lab and its intended lesson. “A spectroscope is a device that measures the spectrum of light” (Ball, 2014). More specifically a spectroscope is an instrument designed to split light from different sources into wavelengths. Humans are able to see these wavelengths as different colors. Noting the difference in colors between various light sources, those studying a given light source can identify elements of the light source.
The obtained NMR spectra was very similar to that of the predicted results. The methyl hydrogen group had a single peak at 2.153 ppm. The results were a little off from the predicted shift of 2.2 – 2.9 ppm but not by much. Next in the spectra, were the hydrogens in the aromatic ring with a range of 7.065-7.436 ppm consisting of multiple peaks, these also matched up to the predicted shift of 6.5-8.0 ppm. The last signal belonged to that of the hydrogen in the amide that had a peak at 7.571 ppm which is well in the range of the predicted shift it 5.0 – 9.0 ppm. Overall the NMR proved that the purified acetanilide had very little impurities shown in the
Spectroscopy Spectroscopy is the study of energy levels in atoms or molecules, using absorbed or emitted electromagnetic radiation. There are many categories of spectroscopy eg. Atomic and infrared spectroscopy, which have numerous uses and are essential in the world of science. When investigating spectroscopy four parameters have to be considered; spectral range, spectral bandwidth, spectral sampling and signal-to-noise ratio, as they describe the capability of a spectrometer. In the world of spectroscopy there are many employment and educational opportunities as the interest in spectroscopy and related products is increasing.
You take voltage measurements by counting the number of divisions a waveform spans on the oscilloscope's vertical scale. Adjusting the signal to cover most of the screen vertically, then taking the measurement along the centre vertical graticule line having the smaller divisions makes for the best voltage measurements. The more screen area you use, the more accurately you can read from the screen.