Solubility of Potassium Chlorate
Solubility is the maximum amount of solid that will dissolve in 100g
of solvent. The solubility of a substance depends on the type of ionic
particles in it. So the solubility of each substance is different. The
formula of solubility is:
SOLUBILITY(g/100g)= (SOLUTE / SOLVENT) * 100
I did an experiment to prove this and find the solubility of potassium
chlorate, an ionic solid.
Apparatus:
2g potassium chlorates, some distilled water, a stand, a clamp, two
beakers, a thermometer, a test tube, and a measuring cylinder.
Method:
1. Put the potassium chlorate into the test tube, and then put 4g
distilled water.
2. Then the solute (which is the salt) dissolves in water (the
solvent) by heating. A solution is made, this is the dissolved solute
in solvent. The solution is left to cool down, and the temperature at
which the solute crystallizes is recorded.
3. Put more 4g water in the test tube. This makes the crystals
dissolve again.
4. Do these things more than 6 times.
5. Make a table of the result.
6. Draw a graph, using a line of best fit.
Table of the results:
Total grams of KClO3 g
Total volume of distilled water cm3
Temperature at which solid come out of solution oc
Solubility of H2O g/100g
2.00
4.00
96
50
2.00
8.00
70
25
2.00
12.00
52
16
2.00
16.00
33
12.5
2.00
20.00
25
10
2.00
24.00
18
8.3
If there was more time I could have repeated this work to make sure
this information was reliable but I could not.
Analysis
Look at the table and the graph above. These results were obtained by
the experiment described. You can use the data and the graph to get
Above is my original data. In the graph, it can be seen that there are
I did accomplish the purpose of the lab. First, I determined the percentage of water in alum hydrate, and the percentage of water in an unknown hydrate. The results are reasonable because they are close to the example results. Second, I calculated the water of crystallization of an unknown hydrate. Furthermore, I developed the laboratory skills for analyzing a hydrate.
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