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Laboratory 10 properties of gases
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Recommended: Laboratory 10 properties of gases
Introduction and Background :
The molar mass of a gas relates to the number of grams in one mole of that particular gas and all molar masses can be found on the periodic table of the elements. The objective of this lab is to compare the theoretical value of butane gas’s, C4H10 (g), molar mass with an experimental value where the gas from a lighter was released and measured by testing if the water displacement method, where a graduated cylinder is inverted in water and gas is released beneath it and trapped in the cylinder, is reliable for collecting data due to it being combined with water vapour as well. After the volume and mass of the gas released are measured, the number of moles can be found by subbing all known variables, including temperature
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R is the universal constant in this equation with a value of 8.314 L·kPa/K·mol.
By finding the number of moles, the molar mass of butane can be calculated using the formula :
Where, again, n is moles, M is the molar mass of butane in g/mol, and m is the mass in grams, found by subtracting the resulting mass of the lighter after drying from the initial mass.
The theoretical and experimental values of the molar mass of butane gas will be very similar, proving the accuracy of the periodic table of elements. The prediction for the molar mass of butane gas can be found by adding together the molar masses of carbon and hydrogen in accordance to butane’s formula of C4H10:
Molar mass of butane = (periodic table molar mass of carbon x number of carbon atoms in
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This reading is the same for the total pressure occupying the graduated cylinder due to all measurements being taken when the level in the cylinder was equal with that of the bin water, equalizing the pressures on the outside and the inside.
The partial pressure of water vapour in the room at 21°C is 2.49 kPa (see table one in References). With both the pressure of the atmosphere leveled with the water in the cylinder and the partial pressure of the water vapour combined with the butane gas, Dalton’s law of partial pressures can be applied to determine the partial pressure of just the butane gas.
The partial pressure of the butane gas is 93.2 kilopascals. The temperatures of both the water used in the bin and of the room were measured and came to be 18°C for the room and 21°C for the bin water, which remained 21°C even at the end of the lab. In kelvins, this comes out to (273.15 + 21) 294.15, 294 K going to three significant digits. The volume at the end of the lab of the gas in the graduated cylinder was 0.400 L when the level of water in the cylinder was level with that of the water in the bin, so equal pressures were acting upon them
Reconstruction began in 1865 and ended in 1877. Reconstruction is known as the rebuilding of the U.S. following the Civil War where they would allow southern's back into the union.The military then organized for new elections, which were three groups and they were; freedmen, carpetbaggers, and
Furthermore, using a graduated cylinder with markings below the 100 mL line would have allowed for more accurate measurements of the initial volume of air in the graduated cylinder.
Our procedure though was not without its mistakes. These mistakes are vital because they affect the data we conclude. Theoretically, according to the balanced chemical equation, for every mole of hydrated cobaltous chloride that is being heated, the decomposition ensures that the compound decomposes into one mole of cobalt(II) chloride and six moles of gaseous water vapor. Thus, in theory we should lose the mass equal to six moles of water vapor in each trial. Unfortunately, this is not the case because we don’t have perfect lab conditions and factors such as the time heated, utilization of the same crucible, and the inconsistency of magnitude of the flame from the Bunsen burner all contribute to differences in mass percent change for each
Mass of O = Mass of crucible, cover, KClO3 and MnO2 after heating (Step # 11) - Mass of crucible, cover, KClO3 and MnO2 before heating (Step # 5)
Evaluation I think that the method used in the experiment is not very accurate because the way we measure the amount of gas produced is not very
The first step that we took to accomplish our goal was to put on our safety goggles and choose a lab station to work at. We received one 400ml beaker, one polyethylene pipet, two test tubes with hole rubber stoppers, two small pieces of magnesium (Mg), one thermometer and a vial of hydrochloric acid (HCl). We took the 400ml beaker and filled it about 2/3 full of water (H20) that was 18 OC. Then we measured our pieces of Mg at 1.5 cm and determined that their mass was 1.36*10-2 g. We filled the pipet 2/3 full of HCl and poured it into one of the test tubes. Then, we covered the HCl with just enough H2O so that no H2O would be displaced when the stopper was inserted. After inserting the stopper, we placed the Mg strip into the hole, inverted the test tube and placed it in the 400ml beaker. HCl is heavier than H2O, so it floated from the tube, into the bottom of the beaker, reacting with the Mg along the way to produce hydrogen gas (H2). We then measured the volume of the H2, cleaned up our equipment and performed the experiment a second time.
The oxygen atom is joined to the hydrogen atom as well as the carbon atom, which makes the oxygen a part of a hydroxyl group. These atoms are generally part of a hydrocarbon chain. These alcohols can take away water from the body, in which a hydrocarbon chain has replaced a hydrogen atom. Alcohols have a general structure of CnH2n+1OH. The aim of this investigation is to see the link between the number of carbon atoms in a fuel with the amount of energy it releases.
Determining the Relative Atomic Mass of Lithium An experiment has been carried out to determine the relative atomic mass of Lithium by using two different types of methods The first method that was carried out was to determine the volume of Hydrogen produced. In this experiment a fixed amount of Lithium was used, in my case it was 0.11g. At the end of this experiment, the volume of Hydrogen gas I collected was 185cm³. Then using the solution of lithium hydroxide made from experiment one, I used it in the titrating experiment, to find out the total volume of Hydrochloric acid used to titrate the lithium hydroxide. RESULTS TABLE Experiment Initial Volume ( cm³) Final Volume ( cm³) Total volume Of HCl used ( cm³) Rough 0.2 30.3 30.1 1 6.3 35.8 29.5 2 2.7 32.0 29.3 Average 29.6 CONCLUSION Method 1 [IMAGE]2Li (s) + 2H20(l) LiOH(aq) + H2(g) Number of moles of Hydrogen. Volume of hydrogen gas was 185 cm³. Weight of Lithium was 0.11g. N = __V__ _185_ = 0.0077 MOLES 24000 24000 Number of moles of Lithium.
I am going to test how the energy output per mole in the combustion of
Sources of Error in Our Implementation Systematic errors > The temperatures on the mercury thermometer may be inexact e.g. may be out by one degree centigrade. > It has been assumed the volume of gas is contained in a compete cylinder when in fact this is not necessarily true, due to: o Spherical shape of the sulphuric bead above it o Residue in the tube o Changes of diameter within cylinder > The volume of air is being partly compresses by the weight of the sulphuric acid bead above it. Therefore the volume may not increase/decrease in proportion to how it would do naturally Random Errors =
(g) Change in mass (g) Methanol 20 170.00 167.08 2.92 Ethanol 20 170.00 167.77 2.23 Propan-1-ol 20 170.00 168.03 1.97 Butan-1-ol 20 170.00 168.16 1.84 Pentan-1-ol 20 170.00 168.24 1.76 Having found these results I then worked out the combustion per mole of alcohol. Alcohol Mass of water heated (g) Heat evolved during reaction (J) Change in mass of burner (g) Combustion of one mole of alcohol (kJ/mole)
When the liquid level in both arms is the same, the pressure of the sample of gas inside the closed end must equal the pressure of the external atmosphere since the downward force on the two columns of liquid is then equal. When the liquid levels are unequal, the pressures must differ. The difference in pressure can be measured in units of length of the vertical column of liquid. The mm Hg, or its modern version the torr, originated in this use of the manometer. Mercury is particularly convenient for use in manometers (and barometers) because at room temperature it has low vapor pressure, does not wet glass, and has a high density. Other liquids such as linseed oil or water have also been used in manometers.
The last part of experiment 5, was learning about specific gravity and temperature. Specific gravity does not have any units, it is unitless. When measuring for the temperature, we used a thermometer to calculate the Celsius of the water, 10% sodium chloride, and isopropyl alcohol. The specific gravity uses a hydrometer to measure the gravity of the liquids. Using the hydrometer, to figure out the measurements we have to look at it from top to bottom. The water for specific gravity was .998 while the temperature of it was 24