Magnesium Oxide Synthesis Lab Report

Easha Naik

Megan Reiff, Emily Netterville

Block 4

21 September 2016

Magnesium Oxide Production Lab

Purpose:

In this experiment ,you precisely weigh a sample of magnesium metal, and then heat the sample in the air. Magnesium metal reacts with the oxygen (O2) of the air to form Magnesium Oxide (MgO2). 2Mg + O2 2 MgO [Synthesis]

After the magnesium sample has reacted completely, the magnesium oxide product is determined. From these two masses, the percentage composition of the magnesium oxide is to be calculated.

Data/Results:

Parameters Measures

•Mass of crucible and cover

27.88 grams

•Mass of crucible, cover and magnesium

28.80 grams

•Mass of magnesium

0.92 grams

•Mass

•Mass of oxygen

0.54 grams

Calculations:

•Mass of magnesium ribbon = Mass of crucible, cover and magnesium ribbon - Mass of crucible and cover = 28.80 g - 27.88 g = 0.92 g

•Mass of the magnesium oxide produced = Mass of crucible, cover and magnesium oxide - Mass of crucible and cover = 29.36 g - 27.88 g = 1.48 g MgO

•Mass of oxygen reacted with magnesium = Mass of magnesium oxide - Mass of magnesium = 1.48 g - 0.92 g = 0.56 g O

•Percent of magnesium in magnesium oxide = MgO = 24.3 g + 16 g = 40.3 g/mol

% of Mg = 24.3g10040.3 g/mol= 60.3 %

•Percent of oxygen in magnesium oxide = MgO = 24.3 g + 16 g = 40.3 g/mol

% of O = 16 g10040.3 g/mol = 39.7 %

•Empirical formula of magnesium and oxygen =

Mg O

60 g 40 g

60 g24 g/mol 40 g16 g/mol

= 2.5 mol 2.5 mol

2.5 mol2.5 mol 2.5 mol2.5 mol

= 1 1

MgO

•Molecular formula of the compound magnesium oxide

0.92 g Mg1 mol Mg24 g Mg= 0.03833333 mol

0.56 g O 1 mol O16 g O= 0.035 mol (both have the same ratios, its 1)

= MgO