Investigating Transpiration in Plants
Hypothesis
I predict that the plant will loose more water through transpiration
when the fan is closer to the plant. I think that the distance of the
fan from the plant and the water loss are inversely proportional, that
is the greater the distance between fan and plant, the smaller the
percentage loss of mass.
I predict also that at a certain distance, the fan will no longer have
an effect, or minimal effect, on the transpiration of the plant and
the water loss will be constant. At this point the best fit line will
be a near-horizontal line close to the axis, showing virtually zero
water loss (excluding evaporation and other effects). These two
predictions together suggest that the best fit for the two trends
described will be a curve as shown..
Analysis (see graph overleaf)
=============================
The graph shows the relationship between the distance of the fan from
the plant, and the % change of mass in the plant.
From the graph, I can see that:-
1. The plant is losing water/transpiring when placed near a fan,
because all the % changes in mass are negative numbers, and this shows
the mass is going down.
2. There is an anomalous result at 100cm. This is so far away from the
other readings that it should be disregarded.
3. There is a pattern in my results, disregarding the anomalous
result. I can see that there is the greatest water loss when the fan
is closest and least at the furthest distance. For example, at 40cm
the % change of mass is -0.31%, and at 60cm the % change of mass is
-0.28. It is losing more water when the fan is closest, so the water
loss is inversely proportional to the distance of the fan from the
plant. The line of best fit illustrates this trend.
Explanation of Conclusion:
--------------------------
Transpiration happens in the lower half of a leaf, in pores called the
"stomata." Inside the leaf there is a concentration of water vapour
[8.3] In what ways do you think your results would have been different if you had sampled at a different height on the rock?
I also predict that as the light is moved closer to the plant there will be more bubbles (oxygen) produced due to the increase of photosynthesis speed explained above. So in conclusion I predict that the more light intensity there is on the plant the faster the rate of photosynthesis there will be.
1. In response to light, phytochrome undergoes a change in shape that leads to the activation of
Experiment #1: The purpose of this experiment is to investigate the effects of baking soda and light intensity on the rate of photosynthesis of green spinach leave through the observation of floating disk.
The Effect of Light Intensity on the Rate of Oxygen Production in a Plant While Photosynthesis is Taking Place
An Analysis and Evaluation of Data from Photosynthesis Experiments Graph analysis This is my analysis for the investigation in to the affect of light intensity on the rate of photosynthesis to the Canadian pondweed, elodea. In the results the pattern is that when the light intensity is higher the readings are generally higher. On the graph the less the light intensity the lower the gradient of the curve. the equation for the photosynthesis process is; CO2 + 2H2O + Light Energy = =
So using this formula but with the data we collected from our first attempt, this is what it would look like; Tan(60°) x 23m = 39m. As you can tell this answer collected from our first attempt is very well incorrect, but at the time, our group did not know this.
I am going to carry out an experiment to measure the change in mass of
m= 10km2 x 1000m x 1000m = 107m2 107m2 x 15= 1.5 x 1.8m3 = 1.5 x 1011kg
find the rate I have to find the mass change in 1 hour, and I will
An Experiment to Investigate Osmosis in Plant Tissue. Aim: To conduct an investigation to compare the osmotic behavior of the osmotic animal. two types of plant tissue in varying concentrations of sucrose. solution. Then we can find the solution.
Photosynthesis will occur at a faster rate when the plant is exposed to the sun, than when it is not exposed to sunlight.
rest mass is Me <approximately equal> 9.1 x 10 -28 g, about 1/1836 of the mass
Both graphs and data tables show that no anomalous results were present. This is evident within the data as no one point cause a major shift in the trend of the results.
the distance from the light source to the plant. Output - The rate of photosynthesis is to be measured by counting the bubbles of oxygen produced by the plant every two minutes, and therefore finding the rate of photosynthesis. Control - The amount of water available to the Elodea will stay the same. same level as the 400 cm3 beaker. The colour of the lamp will stay the same (yellow) as to plants Chlorophyll easily absorbs blue light.