Identifying an Organic Unknown Aim: In this investigation I will get a number of unknown organic compounds. Which i have to identify by using a number of different chemical and physical techniques. The only thing is known about the compound is that it contains one of the functional group: alcohol, aldehyde, ketone, carboxylic acid, phenol and ester. Therefore I devised a sequence of tests that would identify which one of the groups the sample contains. The flow chart below shows the chemical techniques, which I will use to identify the functional group of the unknown. 1: Test with universal indicator. [IMAGE] Turn red turn And other colour. 2: Test with bromine water 3: test with 2, 4 DNPH [IMAGE][IMAGE] [IMAGE][IMAGE] [IMAGE][IMAGE] Decolourises No orange/yellow No [IMAGE][IMAGE]Bromine water Change precipitate precipitate 4: Phenol carboxylic acid 5: Test with an acidified potassium dichromate
As a final point, the unknown secondary alcohol α-methyl-2-naphthalenemethanol had the R-configuration since it reacted the fastest with S-HBTM and much slower with R-HBTM. TLC was a qualitative method and ImageJ served as a quantitative method for determining which reaction was the faster esterification. Finally, 1H NMR assisted in identifying the unknown from a finite list of possible alcohols by labeling the hydrogens to the corresponding peaks.
The purpose of the Unknown White Compound Lab was to identify the unknown compound by performing several experiments. Conducting a solubility test, flame test, pH paper test, ion test, pH probe test, conductivity probe test, and synthesizing the compound will accurately identified the unknown compound. In order to narrow down the possible compounds, the solubility test was used to determine that the compound was soluble in water. Next, the flame test was used to compare the unknown compound to other known compounds such as potassium chloride, sodium chloride, and calcium carbonate. The flame test concluded that the cation in the unknown compound was potassium. Following, pH paper was used to determine the compound to be neutral and slightly
The goal of this two week lab was to examine the stereochemistry of the oxidation-reduction interconversion of 4-tert-butylcyclohexanol and 4-tert-butylcyclohexanone. The purpose of first week was to explore the oxidation of an alcohol to a ketone and see how the reduction of the ketone will affect the stereoselectivity. The purpose of first week is to oxidize the alcohol, 4-tert-butylcyclohexanol, to ketone just so that it can be reduced back into the alcohol to see how OH will react. The purpose of second week was to reduce 4-tert-butylcyclohexanol from first week and determine the effect of the product's diastereoselectivity by performing reduction procedures using sodium borohydride The chemicals for this lab are sodium hypochlorite, 4-tert-butylcyclohexanone
2-ethyl-1,3-hexanediol. The molecular weight of this compound is 146.2g/mol. It is converted into 2-ethyl-1-hydroxyhexan-3-one. This compounds molecular weight is 144.2g/mol. This gives a theoretical yield of .63 grams. My actual yield was .42 grams. Therefore, my percent yield was 67%. This was one of my highest yields yet. I felt that this was a good yield because part of this experiment is an equilibrium reaction. Hypochlorite must be used in excess to push the reaction to the right. Also, there were better ways to do this experiment where higher yields could have been produced. For example PCC could have been used. However, because of its toxic properties, its use is restricted. The purpose of this experiment was to determine which of the 3 compounds was formed from the starting material. The third compound was the oxidation of both alcohols. This could not have been my product because of the results of my IR. I had a broad large absorption is the range of 3200 to 3500 wavenumbers. This indicates the presence of an alcohol. If my compound had been fully oxidized then there would be no such alcohol present. Also, because of my IR, I know that my compound was one of the other 2 compounds because of the strong sharp absorption at 1705 wavenumbers. This indicates the presence of a carbonyl. Also, my 2,4-DNP test was positive. Therefore I had to prove which of the two compounds my final product was. The first was the oxidation of the primary alcohol, forming an aldehyde and a secondary alcohol. This could not have been my product because the Tollen’s test. My test was negative indicating no such aldehyde. Also, the textbook states that aldehydes show 2 characteristic absorption’s in the range of 2720-2820 wavenumbers. No such absorption’s were present in my sample. Therefore my final product was the oxidation of the secondary alcohol. My final product had a primary alcohol and a secondary ketone
Introduction: Someone in a restaurant has suddenly fallen ill and a mystery powder has been discovered with the victim. As the chief investigator, your duty is to identify the mystery substance through a lab. In this lab, it will consist of five known compounds and one unknown compound. Your job is to distinguish which one out of the five substances is the mystery powder. To figure out the mystery matter you will have to compare their physical and chemical properties and match them with the appropriate compound. Furthermore, you will compare their reactions with water, universal indicator, vinegar and iodine solution to discover what the mystery powder is.
3.) Divide your 30g of white substance into the 4 test tubes evenly. You should put 7.5g into each test tube along with the water.
In the second experiment with the green color, I can safely conclude that the color green in this case is very soluble and we would need longer filter paper, perhaps more time to safely separate the different colors that make up the color green.
Experiment #3: The purpose of this experiment to test the chromatography of plant pigments the alcohol test strip test will be used.
2. With the pipette take two drop of red dye and drop it into the
The late sixties were a time filled with sex, drugs, and rock and roll. A huge part of American culture at the time was focused around these three things. Musicians possessed a tremendous amount of social influence, and like wise, society put a lot of emphasis on the lives and attitudes of musicians. Of the rock groups from this time period, the Beatles were by far the most influential. The British rock group was probably the most catalytic band in rock and roll history. Although they came together in the shadow of the Beatles, another band of that era was Jefferson Airplane. Jefferson Airplane was deemed the first of the San Francisco psychedelic rock groups. Jefferson Airplane was always considered to be a psychedelic rock group, but it was not until later in their existence that the Beatles fell into this category as well. Both groups earned this title for their creative style of rock as well as for their experimentation with drugs. Each of these groups wrote songs that alluded to drug use at one time or another. Two of the most criticized songs from these bands are Lucy in the Sky with Diamonds by the Beatles, and White Rabbit by Jefferson Airplane. White Rabbit is a song latent with drug references. The connection with drugs in Lucy in the Sky with Diamonds is not as clear. Although John Lennon claims that he had no intention of making references to LSD in his song, the abstract lyrics and metaphoric language invite drug connotation. Lucy in the Sky with Diamonds and White Rabbit mirror each other in their association with LSD and their allusions to Alice in Wonderland, but looking into these songs more deeply it is obvious that both artists were writing about escape; escaping reality.
0,74 0,87 1,00 0,49 100... ... middle of paper ... ... some groups had got different leakage of the pigment in the test tubes with water.
- The amount of times the mixture was stirred. We stirred the mixture until the Ammonium Nitrate was dissolved, so the amount of times we stirred after each teaspoon was different.
The point was signaled by a change in color of an indicator that had been added to the acid solution. Indicator is a substance that has distinctly different colors in acidic and basic media. Phenolphthalein was a common indicator which was colorless in acidic and neutral solutions, but reddish pink was result in basic solutions. Strong acid (containing H+ ion) and strong base ( containing OH ) were 100% ionized in water and they were all strong electrolytes.
Executive Summary: The summary basically points out that the market for organic food in India is still petite; there are very few active players in the market however the change in consumers’ perception and the growing trend of being healthy and fit has resulted in an estimation that the market is expected to grow at a CAGR of 13-14% for organic fruits and 10-11% for dairy products over the next five to six years.
There is a lot of variety to choose from in the criminal justice field, but the career I find the most interesting is forensic toxicology. In order to be able to pursue a career in forensic toxicology I think the greatest qualification to have besides that obvious schooling would be a genuine interest2 in the field of science, a future forensic toxicologist should also obtain a bachlors in a scientific field such as biology, clinical chemistry, chemistry, or even pharmaceuticals. Like most jobs in the criminal justice field a clean record is a must without any prior or future criminal offenses or drug charges.