The Moment Of Inertia Of The Flywheel

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The Moment of Inertia of the flywheel was obtained as follow:

I = T / α
= Fa (R2+R1) / (a / R2)
= ((M4g) - (M4a) - (FFr)) (R2+R1) / (( S - ut ) / ( 0.5 t^2 )) / R2
= ((M4g) - (M4(( S - ut ) / ( 0.5 t^2 )) - (FFr)) (R2+R1) / (( S - ut ) / ( 0.5 t^2 )) / R2

• Torque is equal to the product of the moment of inertia and angular acceleration; therefore moment of inertia is equal and was calculated as the quotient of the torque and angular acceleration.
• The torque was calculated as well as the product of the force to accelerate the flywheel and the radius of the axle.
• Force to accelerate the flywheel was calculated by subtracting friction force and force to accelerate the mass from the force due to the earth gravity.
• The friction force was calculated as the product of the mass that cause the hanger to travel vertically downward at constant speed and the earth gravity.
• The force due to gravity was calculated as the product of the mass on the hanger and earth gravity.
• The force to accelerate the mass was calculated as the product of the mass on the hanger and linear acceleration.
• The …show more content…

Theoretical value of I was greater than experimental by 0.0317 kgm^2. The experimental value of I was calculated dividing Torque by angular acceleration thus the Torque should have been larger or angular acceleration smaller.
Angular acceleration was obtained from linear acceleration measuring the time a mass of 1.2kg travelled agreed distance. Delay related to human reaction time possibly affected the measurements of the time the mass accelerated an agreed distance using stop watch. By looking at the equation for linear acceleration the time probably was much longer than 10.7s, the stop watch was stopped too early or distance S was lower than 0.695m. It wasn’t comfortable to measure vertical distance using measuring

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