The Moment of Inertia of the flywheel was obtained as follow:
I = T / α
= Fa (R2+R1) / (a / R2)
= ((M4g) - (M4a) - (FFr)) (R2+R1) / (( S - ut ) / ( 0.5 t^2 )) / R2
= ((M4g) - (M4(( S - ut ) / ( 0.5 t^2 )) - (FFr)) (R2+R1) / (( S - ut ) / ( 0.5 t^2 )) / R2
• Torque is equal to the product of the moment of inertia and angular acceleration; therefore moment of inertia is equal and was calculated as the quotient of the torque and angular acceleration.
• The torque was calculated as well as the product of the force to accelerate the flywheel and the radius of the axle.
• Force to accelerate the flywheel was calculated by subtracting friction force and force to accelerate the mass from the force due to the earth gravity.
• The friction force was calculated as the product of the mass that cause the hanger to travel vertically downward at constant speed and the earth gravity.
• The force due to gravity was calculated as the product of the mass on the hanger and earth gravity.
• The force to accelerate the mass was calculated as the product of the mass on the hanger and linear acceleration.
• The
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Theoretical value of I was greater than experimental by 0.0317 kgm^2. The experimental value of I was calculated dividing Torque by angular acceleration thus the Torque should have been larger or angular acceleration smaller.
Angular acceleration was obtained from linear acceleration measuring the time a mass of 1.2kg travelled agreed distance. Delay related to human reaction time possibly affected the measurements of the time the mass accelerated an agreed distance using stop watch. By looking at the equation for linear acceleration the time probably was much longer than 10.7s, the stop watch was stopped too early or distance S was lower than 0.695m. It wasn’t comfortable to measure vertical distance using measuring
Newton’s second law states that when a net force is applied to an object, that object will experience a change in velocity, and will undergo acceleration. That acceleration is proportional to the net force applied, and inversely proportional to the mass of the object. In other words, the heavier an object is, it will require a greater force to move the object the same amount (e.g., distance) as a lighter object. ( https://www.grc.nasa.gov/www/k-12/airplane/newton2.html)The mathematical equation that expresses Newton’s second law is:
The power of the A pulley is a force multiplier, when x number of pulley(s) are setup. with x number of wheel/roller(s), you pull on the rope or string. providing tension, from this an upward force is created to lift a load. because the lower pulley block is supported by two parts of the rope/string. Example - there are two pulleys with one roller each, the mass is. 0.5 metres from the ground.
where 훳 is the same as 훳 in the previous equation. This means the total torque can be measured by summing those two values.
This experiment could have been more accurate if the angle of the slope could have been lowered to stop the trolley from accelerating. The experiment could have also been improved by taking greater care in making sure that the weights didn’t fall off of the trolley after they collided with the trolley. Better weights should have been found for the 1.5kg as the ones used had to be tied together to reach the sufficient weight, thus making them more likely to fall off the trolley. Conclusion: The hypothesis was proven correct for the 500g weight, however, the hypothesis was not proven correct for the 1kg and 1.5kg weights as the momentum before the collision did not equal to the momentum after the collision.
Newton’s Second Law of Motion. It states, “The force acting on an object is equal to the mass of that object times its acceleration (Lucas, paragraph 2).” Mike 's car, which weighs 1,000 kg, is out of gas. Mike is trying to push the car to a gas station, and he makes the car go 0.05 m/s/s. Using Newton 's Second Law, you can compute how much force Mike is applying to the car with this formula ( F= 1,000 x 0.05 which equals 50 newtons). This is easy,
The circle of traction is a important racing concept with applications from physics. From newtons equation f=ma we know that the more force we apply to an o...
F = ma : where F is force; m is the mass of the body; and a is the acceleration due to that particular force
This involves relating the current supplied to the motor, motor shaft rotational speed, motor efficiency, and the power factor as a function of the load of the motor, similar to the figure on page 21 of the Lab Manual.
The important thing to know about an object that is moving on wheels is that its kinetic energy is equal to half of its mass including the wheels(Mb) multiplied by the square of its velocity(V) plus the kinetic energy in the rotating wheels. In this case I am going to assume that all of the mass of the wheels is located on the outer edge (this isn't really the case, but most of the mass is there). Then the kinetic energy of a wheel due to rotation is half of its mass(Mw) multiplied by the square of its radius(r) multiplied by the square of its angular velocity(w) multiplied by two since there are two wheels.
== 1. The flywheel was set as shown with the axle of the flywheel horizontal. A polystyrene tile was placed on the floor to avoid the impact of the mass on the floor. 2. The vernier caliper was used to measure the diameter d of the axle.
The positive acceleration a is used to denote an increasing acceleration. In free fall motion, it is always influenced by the pull of gravity and so, we denote the acceleration as g. The value of g decreases with increasing altitude. At Earh's surface, the value of g is approximately 9.80 m/s2 assuming that AIR RESISTANCE is negligible.
Mathematically, Hooke’s law states that F equals the displacement or extension length multiplies a constant k, or F = k∆l. F is the force in the spring which migh...