Empirical Formula Lab Report

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Recommended: Determination of empirical formula of magnesium oxide report

The purpose of this experiment is to find the empirical formula of the compound MgO commonly referred to as Magnesium Oxide. This empirical formula will be a whole number ratio of the two elements located in the compound. You can achieve this formula by taking the moles of Magnesium and the moles of Oxygen and dividing them. This will give you the ratio of the compound MgO and therefore give you the empirical formula.

The materials for this experiment include Magnesium, a Bunsen burner, a analytical balance, and an evaporation disk. Beginning the experiment the empty evaporating dish is placed on the analytical balance and the mass is recorded. Then, Magnesium is placed in the evaporating dish and put back on the analytical balance and the …show more content…

Then the mass of the evaporating dish plus Magnesium is 45.6041g. The mass of the evaporating dish plus the final compound is 45.6470g. Next, the mass of the Magnesium must be found by subtracting the mass of the evaporating dish plus Magnesium and the mass of the empty evaporating dish (45.6041g-45.4769g) this gives you .1272g of Magnesium. After that you would find the mass of the product by subtracting the mass of the evaporating dish plus the final compound and the mass of the empty evaporating dish (45.6470g-45.2769g) this gives you .1701g. To find the mass of oxygen you subtract the mass of the product and the mass of Magnesium (.1701g-.1272g) this gives you .0429g of oxygen. Next, you would find the moles of Magnesium by taking the mass of Magnesium and dividing it by the amount of Magnesium in a mole which is 24.31g (.1272g divided by 24.31g) this gives you .0052moles. After finding the moles of Magnesium you will want to find the moles of Oxygen. You find this by taking the mass of oxygen and dividing it by the amount of oxygen in a mole which is 16.00g (.0699g divided by 16.00g) this gives you .0044moles. You will use these moles to find the ratio of moles of Magnesium to moles of Oxygen. You divide the moles of Magnesium by moles of Oxygen (.0052mol divided by .0044mol) this gives you 1.18 repeating moles of Magnesium to moles of

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