Compare the Energy Given Out When Alcohols Burn
I am investigating how different types of alcohol's effect the amount
of energy given off.
The types of alcohol used will be;
Alcohol Formulae
· Methanol CH3 OH
· Ethanol C2 H5 OH
· Propanol C3 H7 OH
· Butanol C4 H9 OH
I am going to investigate the amount of energy given out by the
creating of bonds by subtracting the amount of energy needed to break
the bonds to the amount given out from the creating of bonds.
Methanol; C H3 OH + O2 ® CO2 + 2H2O
H
½
H - C - O -H
½
H
-
C - H O - H O = C = O O = O H - H
( 412 ) ( 463 ) ( 743 x 2 ) ( 496 x 1.5 ) ( 463 )
Input : ( 3 x 412 ) + ( 463 ) + ( 360 ) + ( 496 x 1.5 ) = 2803
Output : ( 743 x 2 ) + ( 643 x 4 ) = 3338
Energy out 3338 - 2803 = 535
= 535 kJ
Ethanol C2 H5 OH + 2O2 ® 2CO2 + 3H2O
H H O = O
½ ½ O = O 496 x 3 743 x 4 + 463 x 6
H - C - C - O - H O = O
½ ½
H H
C - H C - C C - O O - H ( 412 x 5 ) ( 348 ) ( 743 ) ( 463 )
2060 + 348 + 743 + 463
3231 + 1488 = 4719 5750 - 4719 = 1030 kJ
Propanol C3 H7 OH + 4.5O2 ® 3CO2 + 4H2O
4458 + 3704= 8162
H H H O = O
½ ½ ½ O = O
H - C - C - C - O - H O = O
Given Equation we have to find out the summation of natural numbers starting from ‘a’ to ‘n’.
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