Nt1320 Unit 4

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Where,  = r/m and A is the amount at the end of n periods, P is the principal value, r is the annual nominal rate, m is number of compounding periods per year,  is the rate per compounding period and n is the total number of compounding periods.
Also the formula for the continuous compound interest,
A=Pe^rt
Where, A is the amount at the end of time t, P is the principal value, r is the annual nominal rate usually expressed as a decimal, and t is total number of compounding years.

If an investment of $100 were made in 1776, and if it earned 3% compounded quarterly, how much would it be worth in 2026?
In order to begin to solve this word problem equation, we are provided with the given information,
P=$100, r = 3% Compounded Quarterly, t …show more content…

Discuss the effect of compounding interest monthly, daily, and continuously (rather than quarterly) on the $100 investment
To see the effect of compounding interest monthly, daily and continuously rather than quarterly, we will have to calculate the values for each of the compounding interest.
Compounded Monthly
The interest rate is compounded monthly, so the total number of compounding periods per year is 12 (monthly) m = 12
Now applying the formula, you must substitute the given variables to find the interest that would be compounded monthly before finding A the amount at the end. i=r/m = i=(3%)/12 = i=0.0025 per month

The given total number of years is t=250, and the total number of compounding periods is given as compounded monthly meaning a total of twelve monthly payments throughout the year n=3000 n=12×250 = n=3000

Now applying the formula
A=P(1+i)^n
A=100(1+0.0025)^3000 = …show more content…

So, i=r/m = i=(3%)/360 = i=0.000083 per day

The given total number of years is 250 calculated in part a. So, again the same process as the previous questions m (t) n=360×250 = n=90,000
Now applying the formula for compound interest, you must substitute all the variables calculated P=100,r=0.03/360,n=90,000
A=P(1+i)^n = A=100(1+0.03/360 )^90000 A=$180,748.53

Therefore, the total investment for compounded daily interest rather than quarterly would be worth 180,748.53

Compounded Continuously
In the third case when interest is compounded continuously, the total number of compounded periods (n) changes, as well as the formula for continuous compound interest is incorporated. The factors of the equation basically stay the same as the previous questions.
We know the continuous compound interest formula is
A=Pe^rt
Inputting the values in the corresponding order of P, r, t as given in the question, we now have
A=100e^(0.03×250) = A=$180,804.24

Therefore, the total investment for compounded continuously rather than compounded quarterly would be recorded as

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