Chemistry
Aim: I am trying to find out whether the equation 2CuCO3 ® Cu2O + 2CO2
+ ½O2 or the equation CuCO3 ® CuO + CO2 is correct for the
decomposition of copper carbonate.
Introduction: This is my background research, this information may
help me when I am trying to see which equation is correct. I have used
the book Chemistry 1 by OCR as my reference.
Relative Atomic Mass: This is the mass of an atom of the element
relative to the mass of an atom of carbon-12 which has a mass of
exactly 12.
Relative Molecular Mass: This is the mass of a molecule of a compound
relative to an atom of carbon-12.
Mole: This is the unit of an atom of substance. One mole of a
substance is the mass that has the same number of particles
(Molecules, Ions or Electrons) as there are atoms in exactly 12g of
carbon-12
Avagadro’s Constant: This is the number of atoms or molecules in one
mole of a substance. It is calculated using (L = 6.01 x 1023)
I will also include the equation for number of moles and volume of gas
formed. I shall use my class notes as my reference.
Number of Moles of gas = Volume of Gas (cm3) = Volume of Gas
(cm3)
Molar Volume (cm3) 24000cm3
Volume of Gas = Number of Moles x Molar Volume (cm3)
= Number of Moles x 24000 cm3
Planning:
Copper has two oxides; Cu2O and CuO
Copper carbonate, CuCO3 decomposes on heating to form one of these
oxides and an equation can be written for each possible reaction:
Equation 1:
2CuCO3 ® Cu2O + 2CO2 + ½O2
Mol Ratio 1 : 0.5 : 1 : 0.25
Tot...
... middle of paper ...
... 64cm3
60cm3
0.33g
80cm3 64cm3
64cm3
Evaluation:
From my experiment I have found that equation 1 seems to be the
correct equation as my results show that it was almost equal every
time to the predicted volume I calculated.
When doing my experiment I could have changed some things which could
have made the result more accurate. I should have waited until the
temperature was at room temperature before taking a reading. I have
calculated any inaccuracies I could have made;
In weighing à accuracy or balance x 100
Average mass measured
= 0.005g x100
0.33g
= 1.52%
In gas syringeà 0.5 x 100
62.7
=0.797%
from both sides, leaving us with ½ V2 = GH. When the above equation is
The equation shows how 1 mol of Na2CO3 reacts with 1 mol of H2SO4, so
Investigationg of Chemical and Physical Changes Why I am conducting this experiment? In order to learn how to recognize chemical and physical changes, I have to carry out this experiment to see different chemical and physical changes of different substance. How can we recognize physical changes and chemical changes? -----------------------------------------------------------
Text Box: CaCO3 + HCl = CaCl2 + CO2 + H2O calcium carbonate + hydrochloric acid = calcium chloride + carbon dioxide + water
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