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determination of empirical formula using magnesium oxide
determination of empirical formula using magnesium oxide
determination of empirical formula using magnesium oxide
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Finding the Empirical Formula for Magnesium Oxide
The Results
In order to work out the ratio for magnesium and oxygen, I will have
to calculate the amount of magnesium and oxygen used.
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From these results, and knowing that the Ar for Magnesium is 24, and
the Ar for Oxygen is 16, I can find the number of moles for Magnesium
and Oxygen.
Investigation 1:
Magnesium = 36.08 - 36.04
= 0.04g
Oxygen = 36.11 - 36.08
= 0.03g
Magnesium Ar = 24 Oxygen Ar = 16
--------------------------------
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Investigation 2:
Magnesium = 36.10 - 36.03
= 0.07g
Oxygen = 36.14 - 36.10
= 0.04g
Magnesium Ar = 24 Oxygen Ar = 16
--------------------------------
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Formula:
Magnesium 42 : 36 Oxygen [ -- 3
-------------------------------
Magnesium 14 : 12 Oxygen [ -- 2
Magnesium 7: 6 Oxygen
= Mg 0
To ensure that my final answer was as accurate as possible, I did not
round any numbers until the end to get the most accurate final
equation. Likewise for test 1, 3, and the average.
Investigation 3:
Magnesium = 36.10 - 36.03
= 0.07g
Oxygen = 36.19 - 36.12
= 0.07g
Magnesium Ar = 24 Oxygen Ar = 16
--------------------------------
Moles:
Magnesium. Mass Oxygen. Mass
Ar Ar
= 0.07 = 0.07
24 16
= 0.002916 = 0.004375
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To ensure that my final answer was as accurate as possible, I did not
round any decimals off until the end to maintain accuracy throughout
the calculation.
Average of Investigation 1, 2, and 3
Magnesium mean = (0.04 + 0.07 + 0.07)
3
= 0.06g
Oxygen mean = (0.03 + 0.04 + 0.07)
3
= 0.047 (2 s.f.)
Magnesium Ar = 24 Oxygen Ar = 16
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