Chemistry

750 Words2 Pages

Chemistry Aim: I am trying to find out whether the equation 2CuCO3 ® Cu2O + 2CO2 + ½O2 or the equation CuCO3 ® CuO + CO2 is correct for the decomposition of copper carbonate. Introduction: This is my background research, this information may help me when I am trying to see which equation is correct. I have used the book Chemistry 1 by OCR as my reference. Relative Atomic Mass: This is the mass of an atom of the element relative to the mass of an atom of carbon-12 which has a mass of exactly 12. Relative Molecular Mass: This is the mass of a molecule of a compound relative to an atom of carbon-12. Mole: This is the unit of an atom of substance. One mole of a substance is the mass that has the same number of particles (Molecules, Ions or Electrons) as there are atoms in exactly 12g of carbon-12 Avagadro’s Constant: This is the number of atoms or molecules in one mole of a substance. It is calculated using (L = 6.01 x 1023) I will also include the equation for number of moles and volume of gas formed. I shall use my class notes as my reference. Number of Moles of gas = Volume of Gas (cm3) = Volume of Gas (cm3) Molar Volume (cm3) 24000cm3 Volume of Gas = Number of Moles x Molar Volume (cm3) = Number of Moles x 24000 cm3 Planning: Copper has two oxides; Cu2O and CuO Copper carbonate, CuCO3 decomposes on heating to form one of these oxides and an equation can be written for each possible reaction: Equation 1: 2CuCO3 ® Cu2O + 2CO2 + ½O2 Mol Ratio 1 : 0.5 : 1 : 0.25 Tot... ... middle of paper ... ... 64cm3 60cm3 0.33g 80cm3 64cm3 64cm3 Evaluation: From my experiment I have found that equation 1 seems to be the correct equation as my results show that it was almost equal every time to the predicted volume I calculated. When doing my experiment I could have changed some things which could have made the result more accurate. I should have waited until the temperature was at room temperature before taking a reading. I have calculated any inaccuracies I could have made; In weighing à accuracy or balance x 100 Average mass measured = 0.005g x100 0.33g = 1.52% In gas syringeà 0.5 x 100 62.7 =0.797%

More about Chemistry

Open Document