The Molecular Formula of Succinic Acid
The relative formula mass is the mass of 1 molecule of succinic acid
compared with 1/12th of the mass of an atom of carbon-12. This is
obtained by adding together the relative atomic masses of the atoms
within the molecule according to its written formula. However we do
not know the exact formula:
HOOC(CH )nCOOH Where n is a whole number
between 1 and 4
So to calculate the relative formula mass I must use the formula m = n
×Mr and rearrange it to make Mr the subject Mr = m
n
However I do not know the number of moles for a given mass. I can
calculate this by preparing a standard solution of the acid and
performing a titration experiment.
Firstly I would like to calculate a likely value of the relative
formula mass given the information above.
Suppose n = 3 then HOOC(CH ) COOH and Mr = 1+(2 x
16)+12+(3x12)+(3x2)+12+(2x16)+1
= 132
To perform the titration I have chosen to use equal concentrations of
acid and alkali at 0.1mols/dm³. This is a low concentration as the
more concentrated the solution, the more rapidly the reaction takes
place. This can be explained by the collision theory as increasing the
concentration of the reactants increases the number of particles
resulting in an increased number of collisions. If the reaction takes
place too rapidly then it will be difficult to identify the exact
point at which the alkali is neutralised and the results will become
less accurate.
To prepare my acid solution I must dissolve an accurately weighed
amount of anhydrous succinic acid to 250cm³/0.25dm³ of water to
achieve a concentration of 0.1mols/dm³. What mass of acid is required
to achieve this concentration?
The mass of Mg + the mass of O2=mass of MgxOx. Knowing the mass of
The unit "mole" was introduced into chemistry around 1900 by Ostwald, and he originally defined this unit in terms of gram. Gram is a unit of mass; but what is the mole a unit of? Ostwald did not say;3 however, several years later, he did make it clear that the concept of mole should be linked to the ideal gas. 4
Walk, Fr. Edward. "How to Calculate Mass." Honors Physics. Du Bois Area Catholic School. Du Bois Area Catholic School, Du Bois. 2 Dec. 2013. Class lecture.
In my experiment, I will use an overall volume of 50 cm³ of 2moles of
as the initial amplitude applied to the system and the process. continues to be a part of A formula that can be used to relate mass applied to a spring system. and time period for oscillations of the system is T = 2ۉ M / k This tells us T2 is proportional to the mass.
Determining the Relative Atomic Mass of Lithium An experiment has been carried out to determine the relative atomic mass of Lithium by using two different types of methods The first method that was carried out was to determine the volume of Hydrogen produced. In this experiment a fixed amount of Lithium was used, in my case it was 0.11g. At the end of this experiment, the volume of Hydrogen gas I collected was 185cm³. Then using the solution of lithium hydroxide made from experiment one, I used it in the titrating experiment, to find out the total volume of Hydrochloric acid used to titrate the lithium hydroxide. RESULTS TABLE Experiment Initial Volume ( cm³) Final Volume ( cm³) Total volume Of HCl used ( cm³) Rough 0.2 30.3 30.1 1 6.3 35.8 29.5 2 2.7 32.0 29.3 Average 29.6 CONCLUSION Method 1 [IMAGE]2Li (s) + 2H20(l) LiOH(aq) + H2(g) Number of moles of Hydrogen. Volume of hydrogen gas was 185 cm³. Weight of Lithium was 0.11g. N = __V__ _185_ = 0.0077 MOLES 24000 24000 Number of moles of Lithium.
m= 10km2 x 1000m x 1000m = 107m2 107m2 x 15= 1.5 x 1.8m3 = 1.5 x 1011kg
Mass of O = Mass of crucible, cover, KClO3 and MnO2 after heating (Step # 11) - Mass of crucible, cover, KClO3 and MnO2 before heating (Step # 5)
find the rate I have to find the mass change in 1 hour, and I will
Mass Pb(NO2)3/ MW Pb(NO3)2 to find the mass of SO4, which equaled 0.1394g, then plugged into the percentage was exactly 55.75% SO4. The begging of the experiment requested that the percentage of SO4 in their fertilizer sample be found and that is exactly what was accomplished by this experiment, and the outcome, demonstrating the ability of my group to preform the requested task presented by the
The Gravimetric Stoichiometry lab was a two-week lab in which we tested one of the fundamental laws of chemistry: the Law of Conservation of Mass. The law states that in chemical reactions, when you start with a set amount of reactant, the product should theoretically have the same mass. This can be hard sometimes because in certain reactions, gases are released and it’s hard to measure the mass of a gas. Some common gases released in chemical reactions include hydrogen, carbon dioxide, oxygen and water vapor. One of the best methods for determining mass in chemistry is gravimetric analysis (Lab Handout).
The spring balance is reasonably accurate for determining the load mass. However, the spring balance weighs 62 grams. Explain how to use the Work (in) = Work (out) principle to verify the mass of the spring balance. In order to determine several parts of the equation needed for the Work-in=Work-out formula you would need to determine effort force which is multiplied by the effort distance to come up with the amount of Work-out.
Moles Volume HCl Volume Water 2 M 10 cm 3 0 cm 3 1.5 M 7.5 cm 3 2.5 cm 3 1 M 5 cm 3 5 cm 3 0.5 M 2.5 cm 3 7.5 cm 3
The mean of two perpendicular measurements was taken. 3. The hanger with appropriate amount of slotted mass was put on the tile. Use the balance to measure the total mass m. 4.