No3 And Ionic Reaction Lab

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Balance the following chemical equations and separate the coefficients by commas and a space respectively (put a 1 if the coefficient is assumed 1): Mg(s)+P4(s)→Mg3P2(s) Explanation: Al(s)+N2(s)→AlN(s) Explanation: 5.2.1 Balancing with polyatomic ions We can balance each atom like we did in the previous example but sometimes it becomes very cumbersome especially when we have the same atom in different compounds. Let’s look at the following reaction: YOU CAN DO THIS, BUT IT WILL BE TEDIOUS: Na2SO4(aq) + Mg(NO3)2(aq) → MgSO4(s) + NaNO3(aq) 2 Na atoms 1 S atom 1 Mg atom 2 N atoms 10 O atoms (4 from SO4 and 6 from (NO3)2) 1 Na atom 1 S atom 1 Mg atom 1 N atom 7 O atoms (4 from SO4 and 3 from NO3) This will become …show more content…

This will often be the case with ionic reactions but not always. Remember there is no magic trick that works all the time. Let’s take a look at this reaction: (NH4)3PO4(aq) + Ca(ClO4)2(aq) → Ca3(PO4)2(s) + NH4ClO4(aq) 3 NH4+ ions 1 PO43– ion 1 Ca atom 2 ClO4– ions 1 NH4+ ion 2 PO43– ions 3 Ca atoms 1 ClO4– ion Since NH4+ and ClO4– are in a one to one ratio for NH4ClO4 on the products side and there are 3 NH4+ ions and 2 ClO4– ions on the reactants side we can put a 6 in front of NH4ClO4 and then balance to make 6 NH4+ ions and 6 ClO4– ions by putting a 2 in front of (NH4­)3PO4 and a 3 in front of Ca(ClO4)2 and see how that works. 2 (NH4)3PO4(aq) + 3 Ca(ClO4)2(aq) → Ca3(PO4)2(s) + 6 NH4ClO4(aq) 6 NH4+ ions 2 PO43– ions 3 Ca atoms 6 ClO4– ions 6 NH4+ ions 2 PO43– ions 3 Ca atoms 6 ClO4– ions By balancing the two polyatomic ions the rest of the ions are balanced as well. Again, this is often the case but not always. Quick Check: 5.2.1.a Balance the following chemical equations and separate the coefficients by commas and a space respectively (put a 1 if the coefficient is assumed 1): …show more content…

Hydrazine (N2H4) is a flammable liquid used in rocket fuel. Balance the chemical reaction which shows its formation from nitrogen gas and ammonia. NH3(l) + N2(g) → N2H4(l) 3 N atoms 3 H

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