Epsom Salt Experiment

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The purpose of this experiment was to determine the amount of water in Epsom Salt and determine whether the amount of water is equal to the theoretical value, when the chemical formula is MgSO4・7 H2O. To check the amount of water in epsom salt, 3g of epsom salt in each crucible 1, 2, and 3 were heated on 495℃. While the epsom salt was heated, white water vapor came out from the crucibles and disappeared in the air. According to the Table 1, as the epsom salt were heated, the mass keep decreased and when those were heated 5th and 6th times, 50 minutes and 60 minutes, there were no significant change in mass. From the Table 2, the leftover amount of anhydrous epsom salt in each crucibles were equal. There were 1.46g of MgSO4 in the crucible after the last heating and 1.54g of H2O was vaporized. Since the result of each trials are same, the standard deviation shows up as 0. By using the molar mass of each compound, MgSO4 got 0.0121mol and H2O got 0.0855mol, which the ratio of MgSO4 and H2O is 1:7.07. The mol ratio shows that when there are one MgSO4, there are 7 H2O. According to the chemical formula of epsom salt, which is MgSO4・7 H2O, the experiment shows that the experiment and the theoretical values are almost same. The random errors of the mass and mol for MgSO4 and H2O are 1.3699% and …show more content…

After measuring the mass of three trials before restarting the experiment, the mass increased about 0.05g. Based on this, we could know that epsom salt could gain water easily from air when it is on the air. This is because the epsom salt is inorganic hydrate. Inorganic hydrate could simply lose water by heat, but also could gain water and try to go back before it was heated if there are no heat. This could change the result of the experiment if the crucibles are cooled for long time because if the epsom salt bound water again, the mass could be

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