Chi Square Test Of Attributes Essay

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5.6 Chi – Square Test of attributes:

General Test Procedure:
In general, Null Hypothesis (H0) and Alternative Hypothesis (H1) in Chi-Square test of Attributes is given as follows:
H0: Attribute A and Attribute B are independent.
H1: Attribute A and Attribute B are not independent. α: Level of significance = 0.05
Test statistics : χ^2= (∑▒∑ (O_ij- E_ij )^2)/E_ij

χ_cal^2= (∑▒∑ (Observed Percentage-Expected Percentage)^2)/(Expected Percentage) χ_cal^2 distribution with (m-1)(n-1) degrees of freedom, where, m : number of rows. n : number of columns.
Critical region : { χ_cal^2 ≥ 〖 χ〗_((m-1)(n-1),α)^2}
Hence critical region is given as follows:

χ_((m-1)(n-1),α)^2

α

Decision Rule: If P-value …show more content…

H1: Satisfaction of bonus and incentives is not independent of types of bank.
Result:
P-value of χ_cal^2≅ 0.00000.
Conclusion:
As P-value less than α we reject H0. Hence, Satisfaction of bonus and incentives is not independent of types of bank.

7) Table 51
Here we are testing independence between two Attributes:
A: Satisfaction of bonus and incentives
B: Types of bank
Hypothesis:
H0 : Satisfaction of bonus and incentives is independent of types of bank.
H1: Satisfaction of bonus and incentives is not independent of types of bank.
Result:
P-value of χ_cal^2≅ 0.00000.
Conclusion:
As P-value less than α we reject H0. Hence, Satisfaction of bonus and incentives is not independent of types of bank.

8) Table 52
Here we are testing independence between two Attributes:
A: Overtime Allowances
B: Types of bank
Hypothesis:
H0: Overtime Allowances is independent of types of bank.
H1: Overtime Allowances is not independent of types of bank.
Result:
P-value of χ_cal^2≅ 0.00000.
Conclusion:
As P-value less than α we reject H0. Hence, Overtime Allowances is not independent of types of bank.

9) Table 52
Here we are testing independence between two Attributes:
A: Job …show more content…

H1: Satisfaction with job is not independent of types of bank.
Result:
P-value of χ_cal^2≅ 0.00000.
Conclusion:
As P-value less than α we reject H0. Hence, Satisfaction with job is not independent of types of bank.

HEALTH
15) Table 59
Here we are testing independence between two Attributes:
A: Health is affected due to work culture
B: Types of bank
Hypothesis:
H0: Health is affected due to work culture is independent of types of bank.
H1: Health is affected due to work culture is not independent of types of bank.
Result:
P-value of χ_cal^2≅ 0.319253.
Conclusion:
As P-value greater than α we may accept H0. Hence, Health is affected due to work culture is independent of types of bank.

16) Table 60
Here we are testing independence between two Attributes:
A: Troubled headache
B: Types of bank
Hypothesis:
H0: Troubled headache is independent of types of bank.
H1: Troubled headache is not independent of types of bank.
Result:
P-value of χ_cal^2≅ 0.061225.
Conclusion:
As P-value greater than α we may accept H0. Hence, Troubled headache is independent of types of bank.
17) Table

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